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dimulka [17.4K]

3 years ago

7

Caleb scored 60 on his first math test. He studied diligently for the next test and earned a score of 90. What is his percent of

increase from the first test to the second test? A. 15% B. 30% C. 50% D. 66 2/3%

1 answer:

Scrat [10]3 years ago

7 0

Your answer would be C. 50%

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You believe the population is normally distributed. Find the 80% confidence interval. Enter your answer as an open-interval (i.e

victus00 [196]

You intend to estimate a population mean μ from the following sample. 26.2 27.7 8.6 3.8 11.6 You believe the population is normally distributed. Find the 80% confidence interval. Enter your answer as an open-interval (i.e., parentheses) accurate to twp decimal places.

Answer:

The Confidence interval = (8.98 , 22.18)

Step-by-step explanation:

From the given information:

mean = $\dfrac{ 26.2+ 27.7+ 8.6+ 3.8 +11.6 }{5}$

mean = 15.58

the standard deviation $\sigma$ = $\sqrt{\dfrac{\sum(x_i - \mu)^2 }{n}}$

the standard deviation = $\sqrt{\dfrac{(26.2 - 15.58)^2 +(27.7 - 15.58)^2 +(8.6 - 15.58)^2 + (3.8 - 15.58)^2 + (11.6 - 15.58)^2 }{5 } }$

standard deviation = 9.62297

Degrees of freedom df = n-1

Degrees of freedom df = 5 - 1

Degrees of freedom df = 4

For df at 4 and 80% confidence level, the critical value t from t table = 1.533

The Margin of Error M.O.E = $t \times \dfrac{\sigma}{\sqrt{n}}$

The Margin of Error M.O.E = $1.533 \times \dfrac{9.62297}{\sqrt{5}}$

The Margin of Error M.O.E = $1.533 \times 4.3035$

The Margin of Error M.O.E = 6.60

The Confidence interval = ( $\mu \pm M.O.E$ )

The Confidence interval = ( $\mu + M.O.E$ , $\mu - M.O.E$ )

The Confidence interval = ( 15.58 - 6.60 , 15.58 + 6.60)

The Confidence interval = (8.98 , 22.18)

7 0

3 years ago

Triangle ABC is similar to triangle FED, find the measure of x. A. X = 9 B. X = 11 C. X = 110 D. X = 231

just olya [345]

Answer:

$A+B+C=130$

$F+E+D=273$

Step-by-step explanation:

From the question we are told that:

Dimension of ABC

A=9

B=11

C=110

Dimension of FED

D=231

Generally the equation for the similar triangles is mathematically given by

$\frac{A}{F}=\frac{B}{E}=\frac{C}{D}$

Therefore solving for F

$\frac{9}{F}=\frac{110}{231}$

$F=\frac{9*231}{110}$

$F=18.9$

Therefore solving for E

$\frac{11}{E}=\frac{110}{231}$

$E=\frac{11*231}{110}$

$E=23.1$

Measure of $\triangle ABC$

$A+B+C=130$

Measure of $\triangle FED$

$F+E+D=273$

5 0

3 years ago

Subtract. Write your answer in simplest form. 8 7/10- 3 4/10

Misha Larkins [42]

Answer:

Exact form: 53/10 , Decimal form: 5.3 , Mixed number form: 5 3/10

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Two teachers compared the mean absolute deviation of the scores from the semester exam they gave to their students. Mrs. Alvarez

Monica [59]

Answer:

C. Mrs. Alvarez's scores were less spread out than Mr. Crawford's scores.

Step-by-step explanation:

Mean Absolute Deviation is one of the Statistical measures which we can you to determine the variation that exist amongst a given set of data

Mean Absolute Deviation can be defined as how far or the distance between one set of data to another set of data.

The smaller the Mean Standard Deviation, the lower the degree of variation in the set of data. The data is less spread out

The larger the Mean Standard Deviation, the higher the degree of variation in the set of data. The data is Largely spread out

We are told in the question that:

Mrs. Alvarez's scores had a lower mean absolute deviation than Mr. Crawford's scores. Our conclusion would be that Mrs. Alvarez's scores were less spread out than Mr. Crawford's scores.

Option 2 is correct.

3 0

4 years ago

What is the output value for the input value of 5?

Tcecarenko [31]

<span>If the relationship is x+4 then
f(5)=5+4
f(5)=9
as an example

</span>

6 0

3 years ago