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3 years ago

At which time is the distance between the tip of the 4. In

Mathematics

2 answers:

Vinil7 [7]3 years ago

8 0

3202hsjsjbejekmwnejeke

ddd [48]3 years ago

3 0

Answer:My name is william schruge and i donot promor\t\te this here interentr pagej ys stop this now

Step-by-step explanation:

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If f(5) and the equation is f(x)=x to the2nd power +2x

scoundrel [369]

The answer would be 35

5 0

3 years ago

Identify the percent of change as an increase or decrease. Then find the percent of change, rounding to the nearest tenth of a p

kap26 [50]

Answer:

-60% decrease

Step-by-step explanation:

60 is the old value and 24 is the new value.

percent change = $\frac{new - old}{|old|}$ x 100%

so for this problem, you can substitute the values given in the formula:

percent change = $\frac{60-24}{|60|}$ x 100% = $\frac{-36}{60}$ x 100% =

-60% (decrease)

3 0

4 years ago

Find a compact form for generating functions of the sequence 1, 8,27,... , k^3

pantera1 [17]

This sequence has generating function

$F(x)=\displaystyle\sum_{k\ge0}k^3x^k$

(if we include $k=0$ for a moment)

Recall that for $|x|$ , we have

$\displaystyle\frac1{1-x}=\sum_{k\ge0}x^k$

Take the derivative to get

$\displaystyle\frac1{(1-x)^2}=\sum_{k\ge0}kx^{k-1}=\frac1x\sum_{k\ge0}kx^k$

$\implies\dfrac x{(1-x)^2}=\displaystyle\sum_{k\ge0}kx^k$

Take the derivative again:

$\displaystyle\frac{(1-x)^2+2x(1-x)}{(1-x)^4}=\sum_{k\ge0}k^2x^{k-1}=\frac1x\sum_{k\ge0}k^2x^k$

$\implies\displaystyle\frac{x+x^2}{(1-x)^3}=\sum_{k\ge0}k^2x^k$

Take the derivative one more time:

$\displaystyle\frac{(1+2x)(1-x)^3+3(x+x^2)(1-x)^2}{(1-x)^6}=\sum_{k\ge0}k^3x^{k-1}=\frac1x\sum_{k\ge0}k^3x^k$

$\implies\displaystyle\frac{x+4x^3+x^3}{(1-x)^4}=\sum_{k\ge0}k^3x^k$

so we have

$\boxed{F(x)=\dfrac{x+4x^3+x^3}{(1-x)^4}}$

5 0

4 years ago

What is the common difference between consecutive terms in the following

lions [1.4K]

The answer is -4 cuh

4 0

3 years ago

The area of a rhombus can be evaluated using the formula 1/2 d1d2 , where d1 represents the measure of one of its diagonals and

Eddi Din [679]

Answer:

Area of the rhombus will be a repeating decimal.

Step-by-step explanation:

In a terminating decimals, numbers get terminated after decimal like

1/4 = 0.25

while in repeating decimals, numbers get repeated after decimal like

1/3 = 0.33333

When we multiply two decimals which are repeating and terminating decimals the result will be a repeating decimal.

Therefore area of the rhombus will be a repeating decimal.

4 0

3 years ago

Read 2 more answers