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Nat2105 [25]
3 years ago
12

How do u write 2.25 in standard form?​

Mathematics
1 answer:
maw [93]3 years ago
8 0

9514 1404 393

Answer:

  2.25

Step-by-step explanation:

The number 2.25 is already in standard form.

___

In the US (and other places), "standard form" is an ordinary decimal number, with the integer part to the left of the decimal point and the fractional part to the right of the decimal point: 2.25.

In the UK (and other places), "standard form" is a number written in scientific notation with a mantissa consisting of the leading non-zero digit to the left of the decimal point, the remaining significant digits to the right of the decimal point, and a multiplier that is 10 to the power appropriate to the place value of the leading digit. When the multiplier is 1, we need not write it.

  2.25 = 2.25×10⁰ (full form) = 2.25 (with superfluous 10⁰ removed)

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48.1 cm 

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6. If 2P and 2Q are complementary angles, m<P = 31º. What is mzQ?
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c

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Read 2 more answers
At a college, 69% of the courses have final exams and 42% of courses require research papers. Suppose that 29% of courses have a
laila [671]

Answer:

a) 0.82

b) 0.18

Step-by-step explanation:

We are given that

P(F)=0.69

P(R)=0.42

P(F and R)=0.29.

a)

P(course has a final exam or a research paper)=P(F or R)=?

P(F or R)=P(F)+P(R)- P(F and R)

P(F or R)=0.69+0.42-0.29

P(F or R)=1.11-0.29

P(F or R)=0.82.

Thus, the the probability that a course has a final exam or a research paper is 0.82.

b)

P( NEITHER of two requirements)=P(F' and R')=?

According to De Morgan's law

P(A' and B')=[P(A or B)]'

P(A' and B')=1-P(A or B)

P(A' and B')=1-0.82

P(A' and B')=0.18

Thus, the probability that a course has NEITHER of these two requirements is 0.18.

3 0
3 years ago
7 times as much as the sum of 1/3 and 4/5
musickatia [10]
1/3+4/5= 17/15
The commun multipleof 3 and 5 is 15.
1/3×5= 5/15
4/5×3= 12/15
5/12+12/15= 17/12

17/12×7= 119/84

119/84

Hope this helps! :)

\(^ ◇^)/
6 0
4 years ago
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