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maw [93]
3 years ago
6

Please help me it dues in 16 minutes is this right?​

Mathematics
2 answers:
dalvyx [7]3 years ago
5 0

Answer:

Yes

Step-by-step explanation:

Slope intercept form is:

y=mx+b

where m is the slope, and b is the y intercept

We are given the slope, it is -3. We are also given the y intercept, (0,4). In this form, the 0 in (0,4) is ignored, and our y intercept is considered to be 4.

Therefore, m is -3, and b is 4.

y=mx+b

y=-3x+4

So, your answer is correct.

Marrrta [24]3 years ago
3 0

Answer:

Yes

Step-by-step explanation:

y = mx + c

m = -3

c = 4

y = -3x + 4

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Can someone plz help me with this one problem plz!!!
larisa86 [58]

Answer:

i guess you just subtract by three

3- 3 = 0

4 - 3 = 1

5- 3 = 2

6- 3 = 3

6 0
3 years ago
Can someone please check my work for this one??
Anton [14]

Answer:

It is correct.  Believe me.  I am in <em>Honors</em> Math.

Step-by-step explanation:

4 0
4 years ago
The figure below shows a right triangle:
il63 [147K]

Answer:

The correct answer is option C.  Cos x

Step-by-step explanation:

<u>Points to remember</u>

<u>Trigonometric ratios </u>

Sin θ  = Opposite side/Hypotenuse

Cos θ = Adjacent side/Hypotenuse

Tan θ = Opposite side/Adjacent side

From the figure we can see that, a right triangle with angles  and sides are given.

<u>To check the options</u>

1) Sin x = Opposite side/Hypotenuse  = p/q

2). Cos y = Adjacent side/Hypotenuse  =p/q

3). cos x= Adjacent side/Hypotenuse  = r/q

4). tan y = Opposite side/Adjacent side = r/p

Therefore the correct answer is option C.  Cos x

5 0
3 years ago
Read 2 more answers
P+6/6+m*n; use m = 4, n = - 1, and p = -6 help plz i dont want to fail
Gemiola [76]

Answer:

The answer is Zero

Step-by-step explanation:

P+6/6+m*n

-6+6/6+4(-1)

0/-2

The answer is Zero

6 0
3 years ago
Our product is 72. The difference between us is 1. What numbers are we?
sweet [91]
Xy = 72
x - y = 1
x = 1 + y

(1+y)y = 72
y + y^2 = 72
y^2 + y - 72 = 0
(y-8)(y+9) = 0
y = 8 , y = - 9

x = 1 + 8
x = 9

y = 8

i am a mathematics teacher. if anything to ask please pm me
4 0
4 years ago
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