Please help me it dues in 16 minutes is this right?

Mathematics

2 answers:

dalvyx [7]3 years ago

5 0

Answer:

Yes

Step-by-step explanation:

Slope intercept form is:

y=mx+b

where m is the slope, and b is the y intercept

We are given the slope, it is -3. We are also given the y intercept, (0,4). In this form, the 0 in (0,4) is ignored, and our y intercept is considered to be 4.

Therefore, m is -3, and b is 4.

y=mx+b

y=-3x+4

So, your answer is correct.

Marrrta [24]3 years ago

3 0

Answer:

Yes

Step-by-step explanation:

y = mx + c

m = -3

c = 4

y = -3x + 4

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Find all solutions of each equation on the interval 0 ≤ x < 2π.

Korvikt [17]

Answer:

$x = 0$ or $x = \pi$ .

Step-by-step explanation:

How are tangents and secants related to sines and cosines?

$\displaystyle \tan{x} = \frac{\sin{x}}{\cos{x}}$ .

$\displaystyle \sec{x} = \frac{1}{\cos{x}}$ .

Sticking to either cosine or sine might help simplify the calculation. By the Pythagorean Theorem, $\sin^{2}{x} = 1 - \cos^{2}{x}$ . Therefore, for the square of tangents,

$\displaystyle \tan^{2}{x} = \frac{\sin^{2}{x}}{\cos^{2}{x}} = \frac{1 - \cos^{2}{x}}{\cos^{2}{x}}$ .

This equation will thus become:

$\displaystyle \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} \cdot \frac{1}{\cos^{2}{x}} + \frac{2}{\cos^{2}{x}} - \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} = 2$ .

To simplify the calculations, replace all $\cos^{2}{x}$ with another variable. For example, let $u = \cos^{2}{x}$ . Keep in mind that $0 \le \cos^{2}{x} \le 1 \implies 0 \le u \le 1$ .