Answer:
13.9 sorry if I'm wrong just trying to help.
Step-by-step explanation:
first plug in your numbers
a*2+ b*2= c*2
12*12= 144
7*7=49
144+49= 193
square root of 193: 13.89244399
rounded to nearest tenth is 13.9
Answer:
Height of the fighter plane =1.5km=1500 m
Speed of the fighter plane, v=720km/h=200 m/s
Let be the angle with the vertical so that the shell hits the plane. The situation is shown in the given figure.
Muzzle velocity of the gun, u=600 m/s
Time taken by the shell to hit the plane =t
Horizontal distance travelled by the shell =u
x
t
Distance travelled by the plane =vt
The shell hits the plane. Hence, these two distances must be equal.
u
x
t=vt
u Sin θ=v
Sin θ=v/u
=200/600=1/3=0.33
θ=Sin
−1
(0.33)=19.50
In order to avoid being hit by the shell, the pilot must fly the plane at an altitude (H) higher than the maximum height achieved by the shell for any angle of launch.
H
max
=u
2
sin
2
(90−θ)/2g=600
2
/(2×10)=16km
I don’t know the answer but I hope someone else does:)
Step-by-step explanation:
whats the equation lol
0.9801. The "9801" is repeatin so just draw the repeating bar above those numbers.
