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NISA [10]
3 years ago
9

If a is the average (arithmetic mean) of 6m and 10, b is the average of 4m and 4, and c is the average of 14m and 16, what is th

e average of a, b, and c in terms of m?
Mathematics
1 answer:
Paha777 [63]3 years ago
4 0

Answer:

6m+7.5

Step-by-step explanation:

the arithmetic mean is the average of two numbers

it is given that a is average of 6m and 10

so a=\frac{6m+10}{2}

b is the average of 4m and 4

so b=\frac{4m+4}{2}

c is the average of 14m and 16

so c=\frac{14m+16}{2}

now the average of a ,b and c is given by

average=\frac{a+b+c}{3}=\frac{\frac{6m+10}{2}+\frac{4m+4}{2}+\frac{14m+16}{2}}{3}=6m+7.5

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To figure out which is not equivalent to the others,, we must solve each option provided. x < -2 is already solved,, so there is no need to do any work that option.
The first step for solving x - 2 < 4 is to move the constant to the right side and then change its sign.
x < 4 + 2
Now add the numbers together to get your final answer.
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This means that we have one option that equals x < -2 and one option that equals x < 6.
Let's now solve 2x < -4 to see what that one equals. In order to solve this,, we need to divide both sides of the inequality by 2.
x < -2
Now we can see that it looks like all of the expressions are equivalent except for x - 2 < 4. Before we can confirm this though,, let's solve for x - 2 < -4. The first step for solving this is to move the constant to the right side and change its sign.
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Now calculate the sum of these two numbers to get your final answer.
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This tells us that all of the options are equivalent except for x - 2 < 4,, or option B.
Let me know if you have any further questions.
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What is the trigonometric ratio for cosn? enter your answer, as a simplified fraction, in the boxes. $$ triangle l m n with righ
hjlf

The trigonometric ratio will be Cos(n)=12/13

<h3>What will be the trigonometry ratio?</h3>

Given is a Right triangle LMN with right angle at M i.e. angle M = 90 degrees.

Given are the sides LM = 15, MN = 36, and LN = 39.

It says to find cos(n) = ?

So opposite side would be LM, adjacent side would be MN, and LN is the hypotenuse.

We know that the cosine ratio is given by :-

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Cos(n)=\dfrac{MN}{LN}

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Hence the required ratio will be   Cos(n)=\dfrac{12}{13}

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