Question

If a is the average (arithmetic mean) of 6m and 10, b is the average of 4m and 4, and c is the average of 14m and 16, what is the average of a, b, and c in terms of m?

Answer 1

Answer:

6m+7.5

Step-by-step explanation:

the arithmetic mean is the average of two numbers

it is given that a is average of 6m and 10

so $a=\frac{6m+10}{2}$

b is the average of 4m and 4

so $b=\frac{4m+4}{2}$

c is the average of 14m and 16

so $c=\frac{14m+16}{2}$

now the average of a ,b and c is given by

$average=\frac{a+b+c}{3}=\frac{\frac{6m+10}{2}+\frac{4m+4}{2}+\frac{14m+16}{2}}{3}=6m+7.5$