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2 years ago

Please help me fast!!!!

Mathematics

2 answers:

NARA [144]2 years ago

7 0

45,000-8059=36941 36941/150=246.3

balandron [24]2 years ago

5 0

The answer is 246.26, doing mental math so I might be wrong

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PERSON 1 IS BOWLING WITH HIS FRIENDS IT COSTS $12DOLLERS FOR 10 PAIRS OF SHOES 25 PEOPLE WERE BOWLING HOW MUCH WOULD IT COST PER

Irina18 [472]

The answer is $300 because you have to multiply 25x12. 10x25=250 and 2x25=50. 250+50=300.

3 0

3 years ago

Find the value of x. Please help

Doss [256]

Answer:

Step-by-step explanation:

height of the hypotenuse:

$\sqrt{60^2-36^2} = \sqrt{3600 - 1296} = \sqrt{2304} = 48$

36 : height = height : x

36 : 48 = 48 : x

x= 48^2/36 = 64

7 0

3 years ago

Read 2 more answers

Work out the size of angle x Next to 164 and 90

Zielflug [23.3K]

Answer:

x=106 degrees

Step-by-step explanation:

I'm going to assume that this is a circle since you didn't give it to me

So you want to add 164 and 90 together and subtract the sum by 360

360-(164+90)=106

So you want to use PEMDAS (order of operations) to solve this

so do what's in the perenthesis first so 164+90=254
Then you want to subtract 254 from 360 so 360-254=106

x=106 degrees

6 0

2 years ago

NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by h ( t ) = − 4.

Oliga [24]

Answer:

$\displaystyle 1)48.2 \: \: \text{sec}$

$\rm \displaystyle 2)3021.6 \: m$

Step-by-step explanation:

<h3>Question-1:</h3>

so when flash down occurs the rocket will be in the ground in other words the elevation(height) from ground level will be 0 therefore,

to figure out the time of flash down we can set h(t) to 0 by doing so we obtain:

$\displaystyle - 4.9 {t}^{2} + 229t + 346 = 0$

to solve the equation can consider the quadratic formula given by

$\displaystyle x = \frac{ - b \pm \sqrt{ {b}^{2} - 4 ac} }{2a}$

so let our a,b and c be -4.9,229 and 346 Thus substitute:

$\rm\displaystyle t = \frac{ - (229) \pm \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}$

remove parentheses:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}$

simplify square:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 52441- 4( - 4.9)(346)} }{2.( - 4.9)}$

simplify multiplication:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 52441- 6781.6} }{ - 9.8}$

simplify Substraction:

$\rm\displaystyle t = \frac{ - 229 \pm \sqrt{ 45659.4} }{ - 9.8}$

by simplifying we acquire:

$\displaystyle t = 48.2 \: \: \: \text{and} \quad - 1.5$

since time can't be negative

$\displaystyle t = 48.2$

hence,

at 48.2 seconds splashdown occurs

<h3>Question-2:</h3>

to figure out the maximum height we have to figure out the maximum Time first in that case the following formula can be considered

$\displaystyle x _{ \text{max}} = \frac{ - b}{2a}$

let a and b be -4.9 and 229 respectively thus substitute:

$\displaystyle t _{ \text{max}} = \frac{ - 229}{2( - 4.9)}$

simplify which yields:

$\displaystyle t _{ \text{max}} = 23.4$

now plug in the maximum t to the function:

$\rm \displaystyle h(23.4)- 4.9 {(23.4)}^{2} + 229(23.4)+ 346$

simplify:

$\rm \displaystyle h(23.4) = 3021.6$

hence,

about 3021.6 meters high above sea-level the rocket gets at its peak?

5 0

2 years ago

492032 word form and expanded form

amm1812

400,000+90,000+2,000+0+30+02=492,032 is the answer put that and you will get a good grade :)

7 0

2 years ago

Read 2 more answers