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Maru [420]
3 years ago
6

Determine the equivalent system for the given system of equations.

Mathematics
2 answers:
lys-0071 [83]3 years ago
6 0

Answer:

4x − 5y = 2

13x − 8y = 26

Step-by-step explanation:

The equivalent system must have the same solution as the given system of equations:

4x − 5y = 2

3x − y = 8

Here we have that:

y = 3x - 8

4x - 5y = 2

4x - 5(3x - 8) = 2

4x - 15x + 40 = 2

-11x = -38

x = \frac{38}{11}

y = 3x - 8 = \frac{3*38}{11} - \frac{88}{11} = \frac{26}{11}

Now, we have to verify which of these systems have this answer:

4x − 5y = 2

13x − 8y = 4

13x - 8y = 4

13\frac{38}{11} - 8\frac{26}{11} = \frac{286}{11} \neq 4

4x − 5y = 2

10x + 3y = 15

10x + 3y = 15

10\frac{38}{11} + 3\frac{26}{11} = \frac{458}{11} \neq 15

4x − 5y = 2

13x − 8y = 26

4x - 5y = 2

4\frac{38}{11} - 5\frac{26}{11} = \frac{22}{11} = 2

13x - 8y = 26

13\frac{38}{11} - 8\frac{26}{11} = \frac{286}{11} = 26

This is the correct answer

So this is the correct answer

4x − 5y = 2

7x + 6y = 10

konstantin123 [22]3 years ago
6 0

Answer:

The answer is

(4x - 5y = 2) and (13x - 8y =26)

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