<span>Find all pairs of consecutive even integers whose sum is greater than 73 but less than 79.
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Answer:
Football. Best player on the worst team.
Step-by-step explanation:
Might as well get that money if the rest of your team sucks.
You can also do the division with remainders to find the answer:
195 ÷ 96 = 2,041666666666667
So you can clearly see that there are more than two but less than three 96s in 195. So multiply 96 by 2 and then substract the result from 195 to find the remainder:
96 * 2 = 192
195 - 192 = 3
It means that in 195 there will fit two 96s with a remainder of 3.
We can also write it as two 96s and 3/96, what can be further simplified to two 96s and 1/32.
Hello,
xy+xz=100==>x(y+z)=100
x/5*(3y+3z)+10=3/5*(x(y+z))+10=3/5*100+10=70
Answer C
