Hello :
the center of this cercle is : O( 0, 0)
calculate the slope m of the line : OA .. A (3,-4)
m= (yA - yO) / (xA- xO)
m = (-4-0)/(3-0)
m= -4/3
if : k the slope of the tangent : k×m = -1 (the tangent perpendiclar of : OA)
k× (-4/3) = -1
k = 3/4
an equation of this tangent is : y - (-4) = (3/4)(x-3)
Answer: 56
Step-by-step explanation: so you have 6 already and x is next to it and it says x=8 so put the eight where next to the six and since there is nothing in the middle than you multiple 6 8 idk the other number
Let f(x) = y.
y = 4x - 12
Let x = 0
y = 4(0) - 12
y = - 12
This leads to the point (0, -12).
Let y = 0.
0 = 4x - 12
1 2 = 4x
12/4 = x
3 = x
This leads to the point (3, 0).
We now graph both points and then connect each point with a straight line.
The domain is all real numbers, reason being, you can put any number for x and get a valid coordinate.
