The answer for that question is no you will need a ratio
in the first half he would have swam 1 km. there are 1000m in a km so 1000/200=5 so he swam the first 200 fly, then a 200 breast, then a 200 fly again, then another 200 breast the finish the first 1 km with a 200 fly. so we switched strokes 4 times.
PS i wouldn't recommend doing a 2 km swim fly and breast
Step-by-step explanation:
using Pythagoras a²+b²=c²
HOWEVER you know the hypotenuse
so it's rearranged to either c²-b²=a² or c²-a²=b²
so 13²-11²
so 169-121
this makes 48
square root 48 is 6.90 inches
this rounds up to <u>7</u><u> </u><u>Inches</u>
I think it will be
(X)=x/4
<span>A linear equation in one variable has a single unknown quantity called a variable represented by a letter. Eg: ‘x’, where ‘x’ is always to the power of 1. This means there is no ‘ x² ’ or ‘ x³ ’ in the equation.The process of finding out the variable value that makes the equation true is called ‘solving’ the equation.An equation is a statement that two quantities are equivalent.For example, this linear equation: x<span> + 1 = 4 </span>means that when we add 1 to the unknown value, ‘x’, the answer is equal to 4.To solve linear equations, you add, subtract, multiply and divide both sides of the equation by numbers and variables, so that you end up with a single variable on one side and a single number on the other side. As long as you always do the same thing to BOTH sides of the equation, and do the operations in the correct order, you will get to the solution.</span><span><span>For this example, we only need to subtract 1 from both sides of the equation in order to isolate 'x' and solve the equation:x<span> + 1 </span>-<span> 1 = 4 </span>-<span> 1</span>Now simplifying both sides we have:x<span> + 0 = 3</span>So:</span><span>x<span> = 3</span></span></span><span>With some practice you will easily recognise what operations are required to solve an equation.Here are possible ways of solving a variety of linear equation types.<span>Example 1, Solve for ‘x’ :</span>x<span> + 1 = </span>-31. Subtract 1 from both sides:x<span> + 1 </span>-<span> 1 = </span>-<span>3 </span>-<span> 1</span>2. Simplify both sides:x<span> = </span>-4<span>Example 2, Solve for ‘x’ :</span>-<span>2x = 12</span>1. Divide both sides by -2:2. Simplify both sides:x<span> = </span>-6<span>Example 3, Solve for ‘x’ :</span>1. Multiply both sides by 3:2. Simplify both sides:<span>x = </span>-6<span>Example 4, Solve for ‘x’ :</span><span>2x + 1 = </span>-171. Subtract 1 from both sides:<span>2x + 1 </span>-<span> 1 = </span>-<span>17 </span>-<span> 1</span>2. Simplify both sides:<span>2x = </span>-183. Divide both sides by 2:4. Simplify both sides:<span>x = </span>-9<span>Example 5, Solve for ‘x’ :</span>1. Multiply both sides by 9:2. Simplify both sides:<span>3x = 36</span>3. Divide both sides by 3:4. Simplify both sides:x = 12<span>Example 6, Solve for ‘x’ :</span> 1. Multiply both sides by 3: 2. Simplify both sides:<span> x + 1 = 21</span> 3. Subtract 1 from both sides:<span> x + 1 </span>-<span> 1 = 21 </span>-<span> 1</span> 4. Simplify both sides:x = 20<span>Example 7, Solve for ‘x’ :</span><span>7(x </span>-<span> 1) = 21</span>1. Divide both sides by 7:2. Simplify both sides:<span>x </span>-<span> 1 = 3</span>3. Add 1 to both sides:<span>x </span>-<span> 1 + 1 = 3 + 1</span>4. Simplify both sides:x = 4<span>Example 8, Solve for ‘x’ :</span>1. Multiply both sides by 5:2. Simplify both sides:<span>3(x </span>-<span> 1) = 30</span>3. Divide both sides by 3:4. Simplify both sides:<span>x </span>-<span> 1 = 10</span>5. Add 1 to both sides:<span>x </span>-<span> 1 + 1 = 10 + 1</span>6. Simplify both sides:x<span> = 11</span><span>Example 9, Solve for ‘x’ :</span><span>5x + 2 = 2x + 17</span>1. Subtract 2x from both sides:<span>5x + 2 </span>-<span> 2x = 2x + 17 </span>-<span> 2x</span>2. Simplify both sides:<span>3x + 2 = 17</span>3. Subtract 2 from both sides:<span>3x + 2 </span>-<span> 2 = 17 </span>-<span> 2</span>4. Simplify both sides:<span>3x = 15</span>5. Divide both sides by 3:6. Simplify both sides:x = 5<span>Example 10, Solve for ‘x’ :</span><span>5(x </span>-<span> 4) = 3x + 2</span>1. Expand brackets:<span>5x </span>-<span> 20 = 3x + 2</span>2. Subtract 3x from both sides:<span>5x </span>-<span> 20 </span>-<span> 3x = 3x + 2 </span>-<span> 3x</span>3. Simplify both sides:<span>2x </span>-<span> 20 = 2</span>4. Add 20 to both sides:<span>2x </span>-<span> 20 + 20 = 2 + 20</span>5. Simplify both sides:<span>2x = 22</span>6. Divide both sides by 2:7. Simplify both sides:x <span>= 11</span></span>
