well, is noteworthy that an x-intercept is when y = 0 or namely is a solution or root of the quadratic, so we know then that the x-intercepts or solutions are at (-1,0) and (3,0), that simply means that
![\bf -8=a(2)(-2)\implies -8=-4a\implies \cfrac{-8}{-4}=a\implies \boxed{2=a} \\\\[-0.35em] ~\dotfill\\\\ y=2(x+1)(x-3)\implies y=2(\stackrel{\mathbb{FOIL}}{x^2-2x-3})\implies y=2x^2-4x-6](https://tex.z-dn.net/?f=%5Cbf%20-8%3Da%282%29%28-2%29%5Cimplies%20-8%3D-4a%5Cimplies%20%5Ccfrac%7B-8%7D%7B-4%7D%3Da%5Cimplies%20%5Cboxed%7B2%3Da%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20y%3D2%28x%2B1%29%28x-3%29%5Cimplies%20y%3D2%28%5Cstackrel%7B%5Cmathbb%7BFOIL%7D%7D%7Bx%5E2-2x-3%7D%29%5Cimplies%20y%3D2x%5E2-4x-6)
Slope = (10 - 5)/(-9 + 15) = 5/6
y = mx + b where m = slope and b = y-intercept
b = y - mx
b = 5 - (5/6) (-15)
b = 5 +12.5
b = 17.5
Equation y = 5/6 x + 17.5
Y-intercept = 17.5
X-intercept when y = 0
So
5/6 x + 17.5 = 0
5/6 x = -17.5
x = (-17.5) (6/5)
x = -21
Answer
Y intercept (0, 17.5 )
X intercept (-21 , 0)
So you know the slope is 2/3. We can write the equation y=mx+b and plug in the value we know to get y=(2/3)x+b. Since the line goes through the point, (-5,6) our equation must be true when the x and y value are plugged into the equation. We get (6)=(2/3)(-5)+b. Solving for b, we get 6=(-10/3)+b then b=28/3. This means our formula is y=(2/3)x+28/3
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Answer:
1. 73.2
2. 90
3. 80
4. 80
Step-by-step explanation:
you will have to divide 3,600 by 50
Answer:
b part is the correct answer
