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S_A_V [24]
3 years ago
6

I am doing a online course on rational expressions, specifically complex fractions without variables, does anyone know what happ

ens in the explanation where I marked it in red. I don't know what they did to get 15/14

Mathematics
1 answer:
Lady bird [3.3K]3 years ago
3 0

Answer:

\boxed{\mathrm{view \ explanation}}

Step-by-step explanation:

<u>9</u>/14 × 5/<u>3</u>

The factors can be canceled if they are factors of both the numerator of the first fraction and the denominator of the second fraction. The factors get cancelled leaving the second fraction to a whole number.

3/14 × 5

(3 × 5)/14

15/14

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If f.) = 2x2 + 1, what is f(x) when x = 3?
Dafna1 [17]

Answer:

19

Step-by-step explanation:

f(x) = 2x^2 +1

Let x =3

f(3) = 2 (3)^2 +1

     = 2 *9 +1

     = 18 +1

     = 19

5 0
4 years ago
What is 1 raised to the fourth power?
nexus9112 [7]

Answer:

1

Step-by-step explanation:

1 * 1 * 1 * 1 = 1

6 0
3 years ago
1) Solve for x<br> 4x + 3 = 3x - 5<br> A) 8<br> C) -8<br> D) 2<br> B) -2
Elodia [21]
4x+3=3x-5
X= -8
C) -8
3 0
3 years ago
The population of a community is known to increase at a rate proportional to the number of people present at time t. The initial
qaws [65]

Answer:

Step-by-step explanation:

Let P be the population of the community

So the population of a community increase at a rate proportional to the number of people present at a time

That is

\frac{dp}{dt} \propto p\\\\\frac{dp}{dt} =kp\\\\ [k \texttt {is constant}]\\\\\frac{dp}{dt} -kp =0

Solve this equation we get

p(t)=p_0e^{kt}---(1)

where p is the present population

p₀ is the initial population

If the  initial population as doubled in 5 years

that is time t = 5 years

We get

2p_o=p_oe^{5k}\\\\e^{5k}=2

Apply In on both side to get

Ine^{5k}=In2\\\\5k=In2\\\\k=\frac{In2}{5} \\\\\therefore k=\frac{In2}{5}

Substitute k=\frac{In2}{5}  in p(t)=p_oe^{kt} to get

\large \boxed {p(t)=p_oe^{\frac{In2}{5}t }}

Given that population of a community is 9000 at 3 years

substitute t = 3 in {p(t)=p_oe^{\frac{In2}{5}t }}

p(3)=p_oe^{3 (\frac{In2}{5}) }\\\\9000=p_oe^{3 (\frac{In2}{5}) }\\\\p_o=\frac{9000}{e^{3(\frac{In2}{5} )}} \\\\=5937.8

<h3>Therefore, the initial population is 5937.8</h3>
7 0
3 years ago
A photo lab usually charges 1.45 per print to make a color print from a color transparency. During a special promotion, the char
Fiesta28 [93]

Answer:

\large \boxed{\math{\$24.05; < 9}}

Step-by-step explanation:

Let n = the number of prints

and C = the total cost.

At the regular price, the formula is

C = 1.45n

During the promotion, you must pay for the first nine prints: 9 × 1.45 = 13.05.

For anything over nine prints (n - 9), you must pay $13.05 plus the promotional cost of $1.10 for each print. The promotional formula is

C = 13.05 + 1.10(n - 9)  {n > 9}

1. Calculate the cost of 19 prints

\begin{array}{rcl}C & = & 13.05 + 1.10(19 - 9)\\ & = & 13.05 + 1.10 \times 10\\ & = & 13.05 + 11.00\\ & = &24.05\\\end{array}\\\text{The cost of 19 prints is $\large \boxed{\mathbf{\$24.05}}$}

2. What number of the prints is a waste of money?

During the promotion, buying fewer than nine prints would be a waste of money, because you would not be taking advantage of the promotional savings.

7 0
3 years ago
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