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3 years ago

11

I need to calculate a=8c-b divided by c, how do I calculate?

1 answer:

laila [671]3 years ago

5 0

Answer:

Step-by-step explanation:

8xC-Bdivide by c

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Mike is playing cards with his sister when he draws a card from a pack of 35 cards numbered from 1 to 35 what is the probability

Ganezh [65]

1/5 because there are 7 numbers divisible by 5 from 1 to 35. 5,10, 15, 20,25,30,35, and out of those there are 35 cards, 7 out of 35 or 7/5 can be simplified to 1/5.

4 0

3 years ago

Read 2 more answers

Write the equation of a line parallel to y= 2x + 2 that passes through the point (-1,-7). Show your work.

oksian1 [2.3K]

Answer:

$\large\boxed{y=2x-5}$

Step-by-step explanation:

The slope-intercept form of an equation of a line:

$y=mx+b$

Parallel lines have the same slope. Therefore if given line is

$y=2x+2$

then the slope of our line is $m=2$ .

We have the equation:

$y=2x+b$

The line passes through (-1, -7). Put the coordinsted pf the point to the equation:

$-7=2(-1)+b$

$-7=-2+b$ <em>add 2 to both sides</em>

$-5=b\to b=-5$

Finally:

$y=2x-5$

6 0

3 years ago

Suppose there are 4 defective batteries in a drawer with 10 batteries in it. A sample of 3 is taken at random without replacemen

SSSSS [86.1K]

Answer:

a.) 0.5

b.) 0.66

c.) 0.83

Step-by-step explanation:

As given,

Total Number of Batteries in the drawer = 10

Total Number of defective Batteries in the drawer = 4

⇒Total Number of non - defective Batteries in the drawer = 10 - 4 = 6

Now,

As, a sample of 3 is taken at random without replacement.

a.)

Getting exactly one defective battery means -

1 - from defective battery

2 - from non-defective battery

So,

Getting exactly 1 defective battery = ⁴C₁ × ⁶C₂ = $\frac{4!}{1! (4 - 1 )!}$ × $\frac{6!}{2! (6 - 2 )!}$

= $\frac{4!}{(3)!}$ × $\frac{6!}{2! (4)!}$

= $\frac{4.3!}{(3)!}$ × $\frac{6.5.4!}{2! (4)!}$

= $4$ × $\frac{6.5}{2.1! }$

= $4$ × $15$ = 60

Total Number of possibility = ¹⁰C₃ = $\frac{10!}{3! (10-3)!}$

= $\frac{10!}{3! (7)!}$

= $\frac{10.9.8.7!}{3! (7)!}$

= $\frac{10.9.8}{3.2.1!}$

= 120

So, probability = $\frac{60}{120} = \frac{1}{2} = 0.5$

b.)

at most one defective battery :

⇒either the defective battery is 1 or 0

If the defective battery is 1 , then 2 non defective

Possibility = ⁴C₁ × ⁶C₂ = 60

If the defective battery is 0 , then 3 non defective

Possibility = ⁴C₀ × ⁶C₃

= $\frac{4!}{0! (4 - 0)!}$ × $\frac{6!}{3! (6 - 3)!}$

= $\frac{4!}{(4)!}$ × $\frac{6!}{3! (3)!}$

= 1 × $\frac{6.5.4.3!}{3.2.1! (3)!}$

= 1× $\frac{6.5.4}{3.2.1! }$

= 1 × 20 = 20

getting at most 1 defective battery = 60 + 20 = 80

Probability = $\frac{80}{120} = \frac{8}{12} = 0.66$

c.)

at least one defective battery :

⇒either the defective battery is 1 or 2 or 3

If the defective battery is 1 , then 2 non defective

Possibility = ⁴C₁ × ⁶C₂ = 60

If the defective battery is 2 , then 1 non defective

Possibility = ⁴C₂ × ⁶C₁

= $\frac{4!}{2! (4 - 2)!}$ × $\frac{6!}{1! (6 - 1)!}$

= $\frac{4!}{2! (2)!}$ × $\frac{6!}{1! (5)!}$

= $\frac{4.3.2!}{2! (2)!}$ × $\frac{6.5!}{1! (5)!}$

= $\frac{4.3}{2.1!}$ × $\frac{6}{1}$

= 6 × 6 = 36

If the defective battery is 3 , then 0 non defective

Possibility = ⁴C₃ × ⁶C₀

= $\frac{4!}{3! (4 - 3)!}$ × $\frac{6!}{0! (6 - 0)!}$

= $\frac{4!}{3! (1)!}$ × $\frac{6!}{(6)!}$

= $\frac{4.3!}{3!}$ × 1

= 4×1 = 4

getting at most 1 defective battery = 60 + 36 + 4 = 100

Probability = $\frac{100}{120} = \frac{10}{12} = 0.83$

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2 years ago

Finding Distance in the Coordinate Plane!

Aleonysh [2.5K]

It is B. the differences are added together

7 0

3 years ago

Solve the equation <br> |x-3| -10=-5

Deffense [45]

Answer:

x=8 x=-2

Step-by-step explanation:

|x-3| -10=-5

Add 10 to each side

|x-3| -10+10=-5+10

|x-3| =5

Now separate into two equations , one positive and one negative

x-3 = 5 x-3 = -5

Add 3 to each side

x-3+3 = 5+3 x-3+3 = -5 +3

x=8 x=-2

5 0

3 years ago

Read 2 more answers