Answer: Hello there!
this type of equations in one dimension (when all the factors are constants) are written as:
h = initial position + initial velocity*t + (acceleration/2)*t^2
First, let's describe the hunter's equation:
We know that Graham moves with a velocity of 1.5 ft/s, and when he is 18 ft above the ground, Hunter throws the ball, and because Graham is pulled with a cable, he is not affected by gravity.
If we define t= 0 when Graham is 18 ft above the ground, the equation for Graham height (in feet) is:
h = 18 + 1.5t
where t in seconds.
Now, the equation for the ball:
We know that at t= 0, the ball is thrown from an initial distance of 5ft, with an initial velocity of 24ft/s and is affected by gravity acceleration g, where g is equal to: 32.2 ft/s (notice that the gravity pulls the ball downwards, so it will have a negative sign)
the equation for the ball is:
h = 5 + 24t - (32.2/2)t^2 = 5 + 24t - 16.1t^2
So the system is:
h = 18 + 1.5t
h = 5 +24t - 16.1t^2
so the right answer is A
Answer:
$75
Step-by-step explanation:
Question:Mr Tarun earns dollar $12.50 a day how much would he earn if he works for 6 days?
Solution:$12.50 in a day
12.50 multiple by 6
=75
Ans.$75
HOPE IT HELPS
CARY ON LEARNING
Answer:
( - x, - y )
Step-by-step explanation:
The starting is always Quadrant I.
270 degrees clockwise from Quadrant I is Quadrant III.
In Quadrant III, the points will be in the form ( - x, - y ).
Answer:
4 i guess i dont rlly know
