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Anna71 [15]
3 years ago
6

What 1 thruogh 100 added up them divided

Mathematics
1 answer:
Marina CMI [18]3 years ago
5 0
We can use the sum of an aritmetic sequence
the sum from n=1 to n=r when the first term is a1 and the nth term is an is
S=\frac{n(a_1+a_n)}{2}
first term is 1
last term is 100
there are 100 terms so n=100

so the sum is S=\frac{100(1+100)}{2}
S=(50)(101)
S=5050
now you want us to divide by 10
5050/10=505


fun fact, gauss (famous math guy) did this when he was younger, legend has it that he was assigned this as an in class assigment to kill time but gauss found a neat pattern, he noticed that adding the end terms wer giving the same sum, example, 100+1=101, 2+99=101, etc, so he just needed to find al the pairs and add them all up




answer is 505
the result is 505
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A dairy farmer wants to mix a 85% protein supplement and a standard 55% protein ration to make 1200 pounds of a high-grade 80% p
mr_godi [17]

The diary farmer should use 1000 pounds of 85 % protien and 55 % of 200 pounds to make 1200 pounds of a high-grade 80% protein ration

<em><u>Solution:</u></em>

Let the amount of 85 % protien supplement be "x"

Then amount of 55 % protien be (1200 - x)

According to given question,

85 % of "x" protien supplement + 55 % of 1200 - x protien used to get 80 % of 1200 pounds

85 % of x + 55 % of (1200 - x) = 80 % of 1200

\frac{85}{100} \times x + \frac{55}{100} \times (1200 - x) = \frac{80}{100} \times 1200\\\\0.85x + 0.55(1200 - x) = 960\\\\0.85x + 660 - 0.55x = 960\\\\0.3x = 960 - 660\\\\0.3x = 300\\\\x = 1000

Pounds of 85 % protien used = 1000 pounds

Then pounds of 55 % protien used = 1200 - 1000 = 200 pounds

Thus he should use 1000 pounds of 85 % protien and 200 pounds of 55 % protien to get 1200 pounds of a high-grade 80% protein ration

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Akimi4 [234]

Answer:----------->

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8 0
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