An ice cream store sells 3drinks, in 4sizes, and 8 flavors. In how many ways can a customer order a drink?

The owner of a used car lot wants to buy many cars at an auction as he can while not spending more than $20000. If he expects th

AleksAgata [21]

Answer:

5

Step-by-step explanation:

Given that:

Total maximum amount that the owner wishes to spend = $20000

Average price of each car = $4000

To find:

How many cars that the owner can expect to buy?

Solution:

Total number of cars that the owner can expect to buy can be found by dividing the total money available with the owner with the average price of each car.

i.e.

$\text{Number of cars expected to be bought} = \dfrac{\text{Total money available with the owner}}{\text{Average Price of car}}$

We have the following values as given in the question statement:

Total money available = $20000

Average price of car = $4000

Therefore, the answer is:

$\text{Number of cars expected to be bought} = \dfrac{20000}{4000} = \bold{5}$

The owner can expect to buy 5 number of cars.

7 0

3 years ago

Someone help me please!

Natasha_Volkova [10]

Answer:

y < -3x + 2

Step-by-step explanation:

The shading is below the line meaning the inequality is less than. Moreover, the line is dashed meaning there is no 'equal to'.

Therefore, the inequality is y < -3x + 2.

5 0

3 years ago

Plz answer the question just tell me were they belong plz worth 10 points and brainlest!

arsen [322]

Answer:

1. 2^x =64 is option number 4. 6

2. x= (2/5)^3 is option number 1. 8/125

3. 3•(3^4) = 3^x is option number 3. 5

4. 16/25 = x^2 is option number 2. 4/5

5 0

3 years ago

Alvin is 15 years younger than Elga. The sum of their ages is 25. What is Elga’s age

Fynjy0 [20]

Elga is 20 years old and Alvin would be 5. Hope this helped.

4 0

3 years ago

The U.S. Census Bureau conducts annual surveys to obtain information on the percentage of the voting-age population that is regi

yan [13]

Answer:

We conclude that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote.

Step-by-step explanation:

We are given that 513 employed persons and 604 unemployed persons are independently and randomly selected, and that 287 of the employed persons and 280 of the unemployed persons have registered to vote.

Let $p_1$ = percentage of employed workers who have registered to vote.

$p_2$ = percentage of unemployed workers who have registered to vote.

So, Null Hypothesis, $H_0$ : $p_1\leq p_2$ {means that the percentage of employed workers who have registered to vote does not exceeds the percentage of unemployed workers who have registered to vote}

Alternate Hypothesis, $H_A$ : $p_1>p_2$ {means that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote}

The test statistics that would be used here Two-sample z test for proportions;

T.S. = $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }$ ~ N(0,1)

where, $\hat p_1$ = sample proportion of employed workers who have registered to vote = $\frac{287}{513}$ = 0.56

$\hat p_2$ = sample proportion of unemployed workers who have registered to vote = $\frac{280}{604}$ = 0.46

$n_1$ = sample of employed persons = 513

$n_2$ = sample of unemployed persons = 604

So, the test statistics = $\frac{(0.56-0.46)-(0)}{\sqrt{\frac{0.56(1-0.56)}{513}+\frac{0.46(1-0.46)}{604} } }$

= 3.349

The value of z test statistics is 3.349.

Now, at 0.05 significance level the z table gives critical value of 1.645 for right-tailed test.

Since our test statistic is more than the critical value of z as 3.349 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote.

5 0

3 years ago