How do i do 4b - 7 - 15b + 3
1 answer:
You might be interested in
Erm
x+y=6
xy=12
x+y=6
y=6-x
sub back
xy=12
x(6-x)=12
6x-x^2=12
x^2-6x=-12
x^2-6x+12=0
quadratic formula
for
ax²+bx+c=0
for
x²-6x+12=0
a=1
b=-6
c=12
and remember that √-1=i
x=3+/-i√3
the numbers are 3+i√3 and 3-i√3
no real numbers tho
x+y=6
xy=12
x+y=6
y=6-x
sub back
xy=12
x(6-x)=12
6x-x^2=12
x^2-6x=-12
x^2-6x+12=0
quadratic formula
for
ax²+bx+c=0
for
x²-6x+12=0
a=1
b=-6
c=12
and remember that √-1=i
x=3+/-i√3
the numbers are 3+i√3 and 3-i√3
no real numbers tho
The answer is A
start by isolating the y variable
the rest of the work is shown here
start by isolating the y variable
the rest of the work is shown here