Ask question

Ask question

All categories

3 years ago

14

How do i do 4b - 7 - 15b + 3

1 answer:

larisa86 [58]3 years ago

8 0

Firs you would do 4b-15b and get -11b. Next you would do -7+3 and get -4. The final expression would be -11b-4

You might be interested in

Find the area of the given triangle. Round the answer to the nearest tenth.

lions [1.4K]

Using Heron's formula:
A = √(p(p-a)(p-b)(p-c)) where a,b,c are the sides of the triangle and p is half the perimeter.
The answer is B. 149.4 square units.

3 0

3 years ago

Read 2 more answers

How to work it out<br> And who drove farther and how many miles farther

OlgaM077 [116]

Easy, just divide
kelly=440mi/8hr=220mi/4hr=110mi/2hr=55mi/1hr
alberto=468mi/9hr=156mi/3hr=52mi/1hr

55>52

kelly drove 55mi in 1 hour
55-52=3
she drove 3 miles more in 1 hour

5 0

3 years ago

9 - 10x = 2x + 1 - 8x

Furkat [3]

Answer:

$x=2$

Step-by-step explanation:

$9 - 10x = 2x + 1 - 8x$

$9-10x=-6x+1$

Subtract 9 from both sides:

$9-10x-9=-6x+1-9$

$-10x=-6x-8$

Add 6x to both sides:

$-10x+6x=-6x-8+6x$

$-4x=-8$

Divide both sides by -4:

$\frac{-4x}{-4}=\frac{-8}{-4}$

$x=2$

8 0

3 years ago

Read 2 more answers

Please help me :(((((

notsponge [240]

question 3: -2

question 4: 0

Ordered pairs in a graph go in the sequence of (x, y)

6 0

2 years ago

What is the equation of the line perpendicular to Y-3x+1 that passes through the point (12,-6)?

erma4kov [3.2K]

Answer:

$3y + x = -6$

Step-by-step explanation:

Given

y = 3x + 1

Required

Equation of line that passes through (12,-6) and is perpendicular to y = 3x + 1

First, the slope of the line has to be calculated;

Th slope of a line is the coefficient of x in its linear equation;

This implies that the slope of y = 3x + 1 is 3

Having calculated the slope of the first line;

The relationship between both lines are perpendicularity; this implies that $m_1 * m_2 = -1$

Where m_1 = 3 and m_2 is the slope of the secodnd line

$m_1 * m_2 = -1$ becomes

$3 * m_2 = -1$

Divide both sides by 3

$\frac{3 *m_2}{m_2} = \frac{-1}{3}$

$m_2 = \frac{-1}{3}$

The equation of the line can be calculated using the folloing formula

$m = \frac{y - y_1}{x - x_1}$

Where $(x_1, y_1) = (12,-6)$ and $m_2 = \frac{-1}{3}$

The equation becomes

$\frac{-1}{3} = \frac{y -- 6}{x - 12}$

$\frac{-1}{3} = \frac{y + 6}{x - 12}$

Cross multiply

$-(x - 12)= 3(y + 6)$

$-x + 12=3y + 18$

Collect like terms

$12 - 18 = 3y +x$

$-6 = 3y + x$

$3y + x = -6$

4 0

2 years ago