Given x^2-5x+c=7, the constant term c will be obtained using the formula:
c=(-b/2a)²
given that a=1 and b=-5 then plugging the values we shall have:
c=(-(-5)/2*1)²
c=(5/2)²
c=25/4
Answer: the constant is 25/4
So what you would want to do is plot the points in a graph, when you do so you line the points and it will give you a triangle.
So in conclusion it should be, a.) Isosceles
The first option hope this helps
x= −29/4
Answer:
Step-by-step explanation:
−7(x+2)=−3(x−5)
Step 1: Simplify both sides of the equation.
−7(x+2)=−3(x−5)
(−7)(x)+(−7)(2)=(−3)(x)+(−3)(−5)(Distribute)
−7x+−14=−3x+15
−7x−14=−3x+15
Step 2: Add 3x to both sides.
−7x−14+3x=−3x+15+3x
−4x−14=15
Step 3: Add 14 to both sides.
−4x−14+14=15+14
−4x=29
Step 4: Divide both sides by -4.
−4x −4
x=29/−4
x= −29/4
s = side length of square
L = s-6 = width of rectangle (shorter side of rectangle)
W = s+1 = length of rectangle (longer side of rectangle)
multiply the length and width to get the area A
A = L*W
A = ( L ) * ( W )
A = (s-6)*(s+1) .............. substitution
A = s^2 + s - 6s - 6 ... use the FOIL rule
A = s^2 - 5s - 6 ......... combine like terms
<h3>Final Answer: s^2 - 5s - 6</h3>