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2 years ago

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The altitude of the hypotenuse of a right triangle divides the hypotenuse into 45 in. and 5 in. segments. What is the length of

the altitude?

1 answer:

miskamm [114]2 years ago

4 0

Answer:

15 in.

Use this website : http://graysonmath.com/wp-content/uploads/2018/10/HM2_6.4-Practice-Key.pdf

Step-by-step explanation:

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Y = -3<br> x - 5y = 7<br> I have the answer I don’t know how to show my work

Leno4ka [110]

Answer:

Step-by-step explanation:

To use substitution in this problem, you find the Y which ='s -3. That we have clear. Now, the second equation becomes x - 5(-3) =7. A negative times a negative is a positive, so 15. Now, we have x + 15 = 7. Subtract 15 from 7 to get x = -8. Your coordinates, or your answer, will be (-8, -3)

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kondaur [170]

Answer:

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Step-by-step explanation:

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2 years ago

Find the length of side AB<br> Give answer to 3 significant figures

Rina8888 [55]

Answer:

AB = 8.857 cm

Step-by-step explanation:

Here, we are given a <em>right angle</em> $\triangle ABC$ in which we have the following things:

$\angle A = 90 ^\circ\\\angle C = 41 ^\circ\\\text{Side }BC = 13.5 cm$

Side <em>BC </em>is the hypotenuse here.

We have to find the side <em>AB</em>.

Trigonometric functions can be helpful to find the value of Side AB here.

Calculating $\angle B$ :

Sum of all the angles in $\triangle ABC$ is $180^\circ$ .

$\Rightarrow \angle A + \angle B + \angle C = 180^\circ\\\Rightarrow 90^\circ + \angle B + 41^\circ = 180^\circ\\\Rightarrow \angle B = 49^\circ$

We know that <em>cosine </em>of an angle is:

$cos \theta = \dfrac{\text{Base}}{\text{Hypotenuse}}\\\Rightarrow cos B = \dfrac{AB}{BC}\\\Rightarrow cos 49^\circ = \dfrac{AB}{13.5}\\\Rightarrow AB = 13.5 \times 0.656\\\Rightarrow AB = 8.857 cm$

So, side AB = 8.857 cm .

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Step-by-step explanation:I used a calculator.

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