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3 years ago

What is the answer to 8 (x+3)?

Mathematics

1 answer:

LuckyWell [14K]3 years ago

6 0

Answer:

<h2>thank you me and brainiest me</h2>

Step-by-step explanation:

Polynomial equation Solving for 8x + 24 = 0

standard form:8(x + 3) =0

Factorization:

8(x + 3) = 0

solutions

x = −24

= −3

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A gravel company sells gravel by the cubic yard and charges a flat delivery fee. The table shows the total cost C based on the a

Sergio039 [100]

Answer:

Step-by-step explanation:

The cost for 0 cubic yards of gravel refers to the y-intercept of the function.

First, we find the constant ratio of change

$r=\frac{284-124}{7-2}=\frac{160}{5}=32$

The constant ratio of change is 32, that means the cost per cubic yard of gravel is $32.

Now, we just subtract this ratio twice to find the relations until we have x = 0.

$124 -32= 92$

So, for 1 cubic yard, the cost is $92.

$92-32=60$

For 0 cubic yards, the cost is $60, that's the y-intercept or the initial condition.

Therefore, the answer is $60.

6 0

3 years ago

I need help please please

miv72 [106K]

Answer:

The value of x is 7.

Step-by-step explanation:

First, you have to make the left side into 1 fraction by making the denormintor the same and make it into simplest form :

$\frac{x}{3} + \frac{x}{6}$

$= \frac{x \times 2}{3 \times 2} + \frac{x}{6}$

$= \frac{2x}{6} + \frac{x}{6}$

$= \frac{2x + x}{6}$

$= \frac{3x}{6}$

$= \frac{x}{2}$

Next you have to multiply both sides by 2 in order to make x the subject :

$\frac{x}{2} = \frac{7}{2}$

$\frac{x}{2} \times 2 = \frac{7}{2} \times 2$

$x = 7$

5 0

3 years ago

Use the quadratic formula to solve the<br> quadratic equation. SHOW ALL WORK.<br> 2 −8+41 = 0

horsena [70]

Answer:

Solving the equation $x^2-8x+41=0$ using quadratic formula we get $x=4+5i \ or \ x=4-5i$

Step-by-step explanation:

We need to solve the equation $x^2-8x+41=0$ using quadratic formula.

The quadratic formula is:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

where a=1, b=-8 and c=41

Putting values in formula and finding x

$$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$\\$x=\frac{-(-8)\pm\sqrt{(-8)^2-4(1)(41)}}{2(1)}$\\$x=\frac{8\pm\sqrt{64-164}}{2}$\\$x=\frac{8\pm\sqrt{-100}}{2}$\\We \ know \ \sqrt{-1}=i\\x=\frac{8\pm10i}{2}\\x=\frac{8+10i}{2} \ or \ x=\frac{8-10i}{2}\\x=4+5i \ or \ x=4-5i$