Answer:
6a^8/3a^4= (6/3)= 2
a^8/a^4= a^4
2a^4
(6/3)(a^8/a^4)= 2a^4
(6/3)(a^(8-4))= 2a^4
Step-by-step explanation:
2 x 5
2+2+2+2+2= 10
2 x 5= 10
Answer: 2 7 0
Step-by-step explanation:
1. We assume, that the number 900 is 100% - because it's the output value of the task.
2. We assume, that x is the value we are looking for.
3. If 900 is 100%, so we can write it down as 900=100%.
4. We know, that x is 30% of the output value, so we can write it down as x=30%.
5. Now we have two simple equations:
1) 900=100%
2) x=30%
where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:
900/x=100%/30%
6. Now we just have to solve the simple equation, and we will get the solution we are looking for.
7. Solution for what is 30% of 900
900/x=100/30
(900/x)*x=(100/30)*x - we multiply both sides of the equation by x
900=3.33333333333*x - we divide both sides of the equation by (3.33333333333) to get x
900/3.33333333333=x
270=x
x=270
now we have:
30% of 900=270
Answer:
y_c = 2 + 10*x
Step-by-step explanation:
Given:
y'' = 0
Find:
- The solution to ODE such that y(0) = 2, y'(0) = 10
Solution:
- Assuming a solution y = Ce^(mt)
So, y' = C*me^(mt)
y'' = C*m^2e^(mt)
- Back substitute into given ODE, we get:
y'' = C*m^2e^(mt) = 0
e^(mt) can not be equal to zero
- Hence, m^2 = 0
m = 0 , 0 - (repeated roots)
- The complimentary function for repeated roots is:
y_c = (C1 + C2*x)*e^(m*t)
y_c = C1 + C2*x
- Evaluate @ y(0) = 2
2 = C1 + C2*0
C1 = 2
-Evaluate @ y'(0) = 10
y'(t) = C2 = 10
Hence, y_c = 2 + 10*x
Answer:
3ab
Step-by-step explanation:
