Question

Find four consecutive odd integers such that the sum of the first three exceeds the fourth by 18?

Answer 1

Let, numbers = x,(x+2),(x+4),(x+6)

A.T.Q,

x+x+2+x+4 = x+6+18

3x+6 = x+24

3x-x= 24-6

2x = 18

x = 9

Numbers would be 9, 11, 13, 15