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2 years ago

5 rate?? my brother doesn't want to helpx me someone help?]'

Mathematics

2 answers:

Luden [163]2 years ago

7 0

Answer:

-5/2 is the reciprocal of -2/5, but the opposite would just be 5/2.

Step-by-step explanation:

S_A_V [24]2 years ago

6 0

Answer:

yes the answer is yes i think im not good at explaing but hope that helps

Step-by-step explanation:

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PLZ HELP!!! Estimate the diameter of a circle with a circumference of 86 cm.

Pepsi [2]

Pi=3.14, So 86 x 3.14= [ 270.04]

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3 years ago

Ben drinks tea at an incredible rate. He drinks 3.5 loiters of tea every 2/3 of an hour. How many of liters of tea does he drink

zysi [14]

First divide 3.5 by 2 which equals 1.75. Then do 1.75*3 which equals 5.25. So he drinks 5.25 liters in one hour.

6 0

3 years ago

Read 2 more answers

one elvis stamp and one liberty stamp cost a total of .63. a sheet of 40 elvis stamps and 20 liberty stamps cost a total of 18.4

gregori [183]

Elvis stamps: 0.29
Liberty stamps: 0.34

6 0

3 years ago

vivi is a drummer for a band. she burns 756 calories while drumming for 3 hours. she burns the same number of calories each hour

Airida [17]

Answer:

252 cph

Step-by-step explanation:

756 divide by 3 is 252

6 0

2 years ago

Let X denote the distance (m) that an animal moves from its birth site to the first territorial vacancy it encounters. Suppose t

andrezito [222]

Answer and Step-by-step explanation: For an exponential distribution, the probability distribution function is:

f(x) = λ. $e^{-\lambda.x}$

and the cumulative distribution function, which describes the probability distribution of a random variable X, is:

F(x) = 1 - $e^{-\lambda.x}$

(a) Probability of distance at most 100m, with λ = 0.0143:

F(100) = 1 - $e^{-0.0143.100}$

F(100) = 0.76

Probability of distance at most 200:

F(200) = 1 - $e^{-0.0143.200}$

F(200) = 0.94

Probability of distance between 100 and 200:

F(100≤X≤200) = F(200) - F(100)

F(100≤X≤200) = 0.94 - 0.76

F(100≤X≤200) = 0.18

(b) The mean, E(X), of a probability distribution is calculated by:

E(X) = $\frac{1}{\lambda}$

E(X) = $\frac{1}{0.0143}$

E(X) = 69.93

The standard deviation is the square root of variance,V(X), which is calculated by:

σ = $\sqrt{\frac{1}{\lambda^{2}} }$

σ = $\sqrt{\frac{1}{0.0143^{2}} }$

σ = 69.93

Distance exceeds the mean distance by more than 2σ:

P(X > 69.93+2.69.93) = P(X > 209.79)

P(X > 209.79) = 1 - P(X≤209.79)

P(X > 209.79) = 1 - F(209.79)

P(X > 209.79) = 1 - (1 - $e^{-0.0143*209.79}$ )

P(X > 209.79) = 0.0503

P(X≤m) = 0.5

$\int\limits^m_0 f({x}) \, dx$ = 0.5

$\int\limits^m_0 {\lambda.e^{-\lambda.x}} \, dx$ = 0.5

$\lambda.\frac{e^{-\lambda.x}}{-\lambda}$ = $-e^{-\lambda.x} + e^{0}$

$1 - e^{-\lambda.m}$ = 0.5

$-e^{-\lambda.m}$ = - 0.5

ln( $e^{-0.0143.m}$ ) = ln(0.5)

-0.0143.m = - 0.0693

m = 48.46

6 0

3 years ago