Question

Log14/3+log11/5-log22/15=log

Answer 1

Answer:

  log(7)

Step-by-step explanation:

  $\log{\dfrac{14}{3}}+\log{\dfrac{11}{5}}-\log{\dfrac{22}{15}}=\log{\dfrac{\dfrac{14}{3}\cdot\dfrac{11}{5}}{\dfrac{22}{15}}}=\log{\dfrac{14\cdot 11}{22}}\\\\=\log{7}$

_____

The applicable rules of logarithms are ...

• log(ab) = log(a) +log(b)
• log(a/b) = log(a) -log(b)

Answer 2

Answer:

s=0.0500826

Step-by-step explanation:

adding 10 as their base

log14/3+log11/5-log22/15=log

swap the sides

10s= log14/3+log11/5-log22/15

divid both sides by 10

log10 14/30+log10 11/50-log10 22/150

s=0.0500826