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abruzzese [7]
2 years ago
10

Log14/3+log11/5-log22/15=log

Mathematics
2 answers:
Vlad [161]2 years ago
8 0

Answer:

  log(7)

Step-by-step explanation:

  \log{\dfrac{14}{3}}+\log{\dfrac{11}{5}}-\log{\dfrac{22}{15}}=\log{\dfrac{\dfrac{14}{3}\cdot\dfrac{11}{5}}{\dfrac{22}{15}}}=\log{\dfrac{14\cdot 11}{22}}\\\\=\log{7}

_____

The applicable rules of logarithms are ...

  • log(ab) = log(a) +log(b)
  • log(a/b) = log(a) -log(b)
Alika [10]2 years ago
7 0

Answer:

s=0.0500826

Step-by-step explanation:

adding 10 as their base

log14/3+log11/5-log22/15=log

swap the sides

10s= log14/3+log11/5-log22/15

divid both sides by 10

log10 14/30+log10 11/50-log10 22/150

s=0.0500826

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Answer:

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