Question

One number is 7 less than a second number. Twice the second number is 7 less than 5 times the first. Find the smaller of two numbers.
Possible answers:
6, -14, 8, 7

Answer 1

N = x-7
2x = 5n-7

2x = 5(x-7)-7
2x=5x-35-7
-3x=-42
x=14
n=7

7 is the answer