All categories

3 years ago

Need help with this problemsE=10ghsolve for g

1 answer:

8 0

Solve for g:
e = 10 g h
e = 10 g h is equivalent to 10 g h = e:
10 g h = e
Divide both sides by 10 h:
Answer: g = e/(10 h)

You might be interested in

Midtown delivery service delivers packages which cost 1.90

Anna71 [15]

I don't get the question u r answering

6 0

3 years ago

Read 2 more answers

ABC is a straight line and angle CBD is 116

shusha [124]

I think this is what your talking about

8 0

3 years ago

PLEASE HELP QUICK QUESTION EARN 20 POINTS

slamgirl [31]

Answer: The correct option is (D) 36.

Step-by-step explanation: We are given to find the value of 'y' that would make OP parallel to LN.

MO = 28 units, OL= 14 units, Pl = 18 units and MP = y = ?

From the figure, we have

if OP ║ LN, then we must have

∠MOP = ∠MLN

and

∠MPO = ∠MNL.

Since ∠M is common to both the triangles MOP and MLN, so by AAA postulate, we get

ΔMOP similar to ΔMLN.

We know that the corresponding sides of two similar triangles are proportional, so

$\dfrac{MO}{ML}=\dfrac{MP}{MN}\\\\\\\Rightarrow \dfrac{MO}{MO+OL}=\dfrac{MP}{MP+PN}\\\\\\\Rightarrow \dfrac{28}{28+14}=\dfrac{y}{y+18}\\\\\\\Rightarrow \dfrac{28}{42}=\dfrac{y}{y+18}\\\\\\\Rightarrow \dfrac{2}{3}=\dfrac{y}{y+18}\\\\\\\Rightarrow 2y+36=3y\\\\\Rightarrow y=36.$

Thus, the required value of 'y' is 36.

(D) is the correct option.

4 0

3 years ago

Read 2 more answers

What is 4km:370m in simplest form help me

yulyashka [42]

I think its 4 3/70 i hope this helps=)

8 0

3 years ago

Read 2 more answers

A 32 foot tall tree casts a shadow that is 48 feet long How far away from the tree is a 6 ft person

dedylja [7]

Answer:

39 feet

Step-by-step explanation:

In the attached diagram

The height of the tree = AB

The height of the man =DE

The length of the shadow =BC

We want to determine how far away from the tree the person is, i.e. |AD|=y

In Triangle ABC

$Tan \theta=\dfrac{32}{48}$

In Triangle CED

$Tan \theta=\dfrac{6}{48-y}$

Therefore:

$Tan \theta=\dfrac{32}{48}=\dfrac{6}{48-y}\\\dfrac{32}{48}=\dfrac{6}{48-y}\\$Cross Multiply\\32(48-y)=48*6\\1536-32y=288\\32y=1536-288\\32y=1248\\Divide both sides by 32\\y=39$

Therefore, the distance of the man from the tree is 39 feet.

7 0

3 years ago