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ivolga24 [154]
3 years ago
8

Use the box-and-whisker plot shown to answer the following question.

Mathematics
2 answers:
Finger [1]3 years ago
6 0
It’s B. Goodbye have a nice day
brilliants [131]3 years ago
4 0

Answer:

15-9=6 So the answer is B. 6

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How to evaluate question number 4
ANTONII [103]

There are 2 ways that spring to mind.

One is to use the definition of the derivative at a point:

f'(c)=\displaystyle\lim_{x\to c}\frac{f(x)-f(c)}{x-c}

In this case, c=0 and f(x)=\sqrt{5-x}. Then

f'(x)=-\dfrac1{2\sqrt{5-x}}\implies f'(0)=\displaystyle\lim_{x\to0}\frac{\sqrt{5-x}-\sqrt5}x=-\dfrac1{2\sqrt5}

- - -

If you don't know about derivative yet (I would think you do, considering this is for a midterm in AP Calc, but I digress), the other way is to rely on algebraic manipulation. Multiply the numerator and denominator by the conjugate of the numerator to get

\dfrac{\sqrt{5-x}-\sqrt5}x\cdot\dfrac{\sqrt{5-x}+\sqrt5}{\sqrt{5-x}+\sqrt5}=\dfrac{\left(\sqrt{5-x}\right)^2-\left(\sqrt5\right)^2}{x\left(\sqrt{5-x}+\sqrt5\right)}=-\dfrac x{x\left(\sqrt{5-x}+\sqrt5\right)}=-\dfrac1{\sqrt{5-x}+\sqrt5}

This is continuous at x=0, so the limit is the value of the expression at x=0:

\displaystyle\lim_{x\to0}\frac{\sqrt{5-x}-\sqrt5}x=-\lim_{x\to0}\frac1{\sqrt{5-x}+\sqrt5}=-\frac1{2\sqrt5}

5 0
4 years ago
The Sun of the interior angles of each polygon is 360 degrees. In the diagram DEFG≈SPQR. Find the value of X and Y.
OLEGan [10]

Answer:

Y=30

Step-by-step explanation:

D+E+F+G=360

D+F=360-106-84=170

D+F=Q+S

Y+38+3Y+12=170

4Y=170-50=120

Y=30

X=4 ..............................

3 0
3 years ago
Evaluate 7y - 2<br> when y = 9
kotykmax [81]

Answer:

The answer is 61.

Step-by-step explanation:

7(9)-2

63-2

61

5 0
3 years ago
Read 2 more answers
The scale for a drawing of a sports field is 5cm:20m. What will the actual length of the field be if you measure 10cm on the dra
Eduardwww [97]

Answer:

french

Je ne sais pas ce que ça veut dire mais c'est une bonne question

Step-by-step explanation:

3 0
3 years ago
Which expression can be used to find the value of x?
larisa [96]

The complete question is missing, so i have attached it.

Answer:

x = 9(sin 42)/(sin 29)

Step-by-step explanation:

We want to find an expression for x.

From the attached image, we can see a triangle with 2 angles given and 2 sides to be 9 and x respectively.

Now, the law of sines says that;

A/sin A = B/sinB = C/sin C

So applying it to this question, we have;

x/sin 42 = 9/sin 29

Thus,

x = 9(sin 42)/(sin 29)

7 0
4 years ago
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