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jasenka [17]
3 years ago
10

A die has 6 faces numbered 1 to 6.On a single roll of die,find the probability of not getting the number 6

Mathematics
1 answer:
aleksley [76]3 years ago
3 0

Step-by-step explanation:

probability of not getting six=5/6

is your answer

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If AC = 14, what is the measure of AD? Round your answer to the nearest hundredth.
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If I could rearrange the alphabet, I’d put ‘U’ and ‘I’ together

Step-by-step explanation:

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Kevin’s grandfather left him 100 shares of Apple Inc. and 40 shares of Ford Motor Company. How much is his stock worth, assuming
umka2103 [35]

Answer:

Step-by-step explanation:

From the problem statement, we can create the following equation:

T = 100A + 40F

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Plugging in the numbers from the problem statement, we get the following:

T = 100(536) + 40(9.85)

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How do you write 0.27% as a decimal?
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Answer:

0.0027

Step-by-step explanation:

0.27%/100=0.0027

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3 years ago
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PLS HELP ME ON THIS PROBLEM ASAP THANK YOU :)
Fed [463]

Answer:

x= 14

Step-by-step explanation:

When the triangles are similar, they should have a similar ratio that makes one side equal to another. In this case, the ratio is 1.5 as 24 divided by 16 is 1.5. Now, taking the side that is "similar" to the x-value which is 21, we divided 21 by 1.5 resulting in x= 14.

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The proportions of blood phenotypes, A, B, AB, and O, in the population of all Caucasians in the United States are approximately
Vanyuwa [196]

Answer:

a. S = {A,B,AB,O}

b. P(A) = 0.41, P(B) = 0.1, P(AB) = 0.04, P(O) = 0.45

c. 0.45 = 45% probability that the person chosen at random has either type A or type AB blood

Step-by-step explanation:

a List the sample space for this experiment.

All possible blood types(A, B, AB or O). So

S = {A,B,AB,O}

b Make use of the information given above to assign probabilities to each of the simple events.

The proportions of blood phenotypes, A, B, AB, and O, in the population of all Caucasians in the United States are approximately .41, .10, .04, and .45, respectively.

So

P(A) = 0.41, P(B) = 0.1, P(AB) = 0.04, P(O) = 0.45

c What is the probability that the person chosen at random has either type A or type AB blood

P(A) + P(AB) = 0.41 + 0.04 = 0.45

0.45 = 45% probability that the person chosen at random has either type A or type AB blood

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3 years ago
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