i. Let t be the line tangent at point J. We know that a tangent line at a point on a circle, is perpendicular to the diameter comprising that certain point.
So t is perpendicular to JL
let l be the tangent line through L. Then l is perpendicular to JL
ii. So t and l are 2 different lines, both perpendicular to line JL.
2 lines perpendicular to a third line, are parallel to each other, so the tangents t and l are parallel to each other.
Remark. Draw a picture to check the steps
The chord 3cm away is 12cm and chord 6cm away is 6cm.
The two perpendicular chords will create a rectangle with the center. each side will be half of the parallel sides length.
First you would simplify the equation <span>(7x²+2x+5)+(3x²-8x-10) lets start with the first part
</span><span>(7x²+2x+5)
</span>7x² + 2x which = 49x + 2x which also = 51x Then you add the last part (+5)
51x + 5
Now you simplify the last part.
<span>(3x²-8x-10)
</span>3x²-8x which=9x - 8x which also = 1x or simply x Then add the last part (-10) Which you'll get x-10
51x + 5) + (x - 10) = 52x -5
so your answer is 52x - 5
Answer:
the valume of the figure is 1271.7
Step-by-step explanation:
