Answer:
The mentioned parental types are c+m- and c-m+. Thus, the recombinants will be c+m+ and c-m-.
Now, the given distance between c and m is 8 map units. Thus, the recombinant frequency is 8% or 0.08.
The total recombinants from 1000 plaques will come out to be 80,
Thus, the recombinants of each type will be 40.
Total parental type will be 920, and therefore, each parental type count will be 460.
Thus, expected c+m- = 460, expected c-m+ = 460, expected c+m+ = 40 and expected c-m- = 40.
A or C
Just choose any of those!
Answer:
i think White Dwarf
Explanation:
We are given that the star has a temperature of 10,000 K and a luminosity of 10^2. According to the HR diagram, a star with the surface temperature of 10,000 K would be a white dwarf and if the star were on the main sequence, then it would have a luminosity nearly 100 times more than that of the sun. However since the actual luminosity is 10,000 times smaller than this, this star must be a white dwarf since it has 10,000 K and 100 aka 10^2 luminosity
Humans would be the answer for this question
