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2 years ago

In the figure, Ð1 and Ð3 are vertical angles, and Ð2 and Ð4 are vertical angles.

Mathematics

1 answer:

Ede4ka [16]2 years ago

4 0

Answer:

mÐ4 = 30°

Step-by-step explanation:

Vertical angles are angles that are opposite to each other, thus are said to be equal.

Since,

i. Ð1 and Ð3 are vertical angles

ii. Ð2 and Ð4 are vertical angles

This implies that the measure of Ð1 and Ð3 are congruent. And also the measure of Ð2 and Ð4 are congruent.

So that, if mÐ2 = 30°, it would be expected that mÐ4 has the same measure. This implies that mÐ4 = 30°.

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After an antibiotic tablet is taken, the concentration of the antibiotic in the bloodstream is modelled by the function C(t)=8(e

Alexxx [7]

Answer:

the maximum concentration of the antibiotic during the first 12 hours is 1.185 $\mu g/mL$ at t= 2 hours.

Step-by-step explanation:

We are given the following information:

After an antibiotic tablet is taken, the concentration of the antibiotic in the bloodstream is modeled by the function where the time t is measured in hours and C is measured in $\mu g/mL$

$C(t) = 8(e^{(-0.4t)}-e^{(-0.6t)})$

Thus, we are given the time interval [0,12] for t.

We can apply the first derivative test, to know the absolute maximum value because we have a closed interval for t.
The first derivative test focusing on a particular point. If the function switches or changes from increasing to decreasing at the point, then the function will achieve a highest value at that point.

First, we differentiate C(t) with respect to t, to get,

$\frac{d(C(t))}{dt} = 8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)})$

Equating the first derivative to zero, we get,

$\frac{d(C(t))}{dt} = 0\\\\8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)}) = 0$

Solving, we get,

$8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)}) = 0\\\displaystyle\frac{e^{-0.4}}{e^{-0.6}} = \frac{0.6}{0.4}\\\\e^{0.2t} = 1.5\\\\t = \frac{ln(1.5)}{0.2}\\\\t \approx 2$