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ICE Princess25 [194]
3 years ago
10

Use the graph to write an explicit function to represent the data and determine how much money Amy earned in week 5.

Mathematics
2 answers:
aleksklad [387]3 years ago
8 0

Answer:

C

Step-by-step explanation:

zalisa [80]3 years ago
3 0

Answer:

3rd option

f(n)=5(3)^{n-1}

f(5)=405

Step-by-step explanation:

So we are given the following points:

(1,5)

(2,15)

(3,45)

(4,135)

This is a geometric sequence because there is a common ratio, 3. That is you can keep multiply 3 to a previous y-coordinate to get the next y-coordinate.

The formula for a geometric sequence is f(n)=a_1 \cdot r^{n-1}

where a_1 is the first term and r is the common ration.

So we have

f(n)=5 \cdot (3)^{n-1}.

If you want to know the fifth term, just plug in 5:

f(5)=5 \cdot (3)^{5-1}

Simplifying:

f(5)=5 \cdot 3^4

f(5)=5 \cdot 81

f(5)=405

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7 - 2x - x4
neonofarm [45]

Answer: (see explanation)

Step-by-step explanation:

terms: 7, 2x, x4

leading coefficient: 7

constant term: 7

I'm sorry I'm unsure how to solve the last question.

8 0
3 years ago
There are 527 pencils,646 erasers and 748 sharpeners. These are to be put in separate packets containing the same number of item
sp2606 [1]

Answer:

  • 31 pencils
  • 38 erasers
  • 44 sharpeners

Step-by-step explanation:

The number of packets is the greatest common divisor of the given numbers of pencils, erasers, and sharpeners.

It can be helpful to look at the differences between these numbers:

  748 -646 = 102

  646 -527 = 119

The difference of these differences is 17, suggesting that will be the number of packets possible.

  527 = 17 × 31

  646 = 17 × 38

  748 = 17 × 44

The numbers 31, 38, and 44 are relatively prime (31 is actually prime), so there can be no greater number of packets than 17.

There will be 31 pencils, 38 erasers, and 44 sharpeners in each of the 17 packets.

_____

We may have worked the wrong problem. The way it is worded, the <em>maximum</em> number of items in each packet will be 527 pencils, 646 erasers, and 748 sharpeners in one (1) packet. The <em>minimum</em> number of items in each packet will be the number that corresponds to the maximum number of packets. Since 17 is the maximum number of packets, each packet's contents are as described above.

17 is the only common factor of the given numbers, so will be the number of groups (plural) into which the items can be arranged.

6 0
3 years ago
Pleas help me find the answer and show the work to this question
lions [1.4K]

Answer:

Leg\ 1 = 8

Leg\ 2 = 15

Step-by-step explanation:

Given: See Attachment

Required

Determine the length of the legs

To do this, we apply Pythagoras theorem.

Hyp^2 = Adj^2 + Opp^2

In this case:

17^2 = x^2 + (2x- 1)^2

Open Bracket

17^2 = x^2 + 4x^2- 2x-2x + 1

17^2 = 5x^2 - 4x + 1

289= 5x^2 - 4x + 1

Collect Like Terms

5x^2 - 4x + 1 - 289 = 0

5x^2 - 4x - 288 = 0

Solving using quadratic formula:

x = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}

So:

x = 8 or x = -7.2

Since, x can't be negative, then:

x = 8

One of the leg is:

Leg\ 1 = x

Leg\ 1 = 8

Leg\ 2 = 2x - 1

Leg\ 2 = 2*8 - 1

Leg\ 2 = 16 - 1

Leg\ 2 = 15

6 0
3 years ago
at a highschool, the length of a class period is 40 minutes. What is the length, in hours, of a class period at the high school?
Viktor [21]

Answer:

2/3 hours

Step-by-step explanation:

40 minutes = 40/60 = 2/3 hours

4 0
3 years ago
Find the average rate of change of f(x)=2x^2-7x from x=2 to x=6
scoundrel [369]

Answer:

Step-by-step explanation:

The average rate of change of a function f between a and b (a< b) is :

R =[f(b)-f(a)] ÷ (a-b)

●●●●●●●●●●●●●●●●●●●●●●●●

Let R be the average rate of change of this function

f(6) = 2×6^2 - 7×6 = 72-42 = 30

f(2) = 2×2^2 - 7×2 = 8-14 = -6

R = [f(6) - f(2)]÷ (6-2)

R = [30-(-6)] ÷ 4

R = -36/4

R = -9

■■■■■■■■■■■■■■■■■■■■■■■■■

The average rate of change of this function is -9

8 0
3 years ago
Read 2 more answers
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