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kramer
3 years ago
8

What is the negative exponent of 1 / 49

Mathematics
1 answer:
jekas [21]3 years ago
6 0
I think 1 / 7 x 7 is the correct answer
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PLEASE HELP ONLY CORRECT PLEASE TY!!
Arte-miy333 [17]

Answer:

The answer is A. "x = -3"

8 0
3 years ago
Sari has a bag containing 6 half dollars. What is the mass of half dollars in Sari's bag when half dollars weighs 11.34 grams?
Fittoniya [83]
Mass of one half dollars = 11.34g
therefore mass of six half dollars = 6*11.34g
                                                       =68.04g
 Ans : mass of 6 half dollars = 68.04g
7 0
2 years ago
Find the perimeter of the figure to the nearest hundredth. perimeter: about cm
nordsb [41]

The perimeter of the figure to the nearest hundredth is 50.26 cm.

<h3>Perimeter of a figure.</h3>

The perimeter of a figure is the sum of the whole sides of the figure.

The perimeter of the figure can be found as follows:

perimeter of the figure = 12 + 5 + 5 + circumference of the semi circle

circumference of the semi circle  = πr

where

  • r = radius

perimeter of the figure = 22 + πr

perimeter of the figure = 22 + 3.14(9)

perimeter of the figure = 22 + 28.26

perimeter of the figure = 50.26 cm

learn more on perimeter here: brainly.com/question/11419989

#SPJ1

6 0
2 years ago
If the side length of a cube is 40 what is the surface area
Elodia [21]
A cube has 6 sides.

A cube is all made up of squares.

So, we need to find the area of one cube and multiply that by 6.

Length * width= area

40*40= 1,600

Multiply that by 6.

1,600*6= 9600

Whatever the unit is after that: in, feet, cm, m, etc- put that after the number with ^2.

9,600 (the unit) ^2

I hope this helps!
~kaikers
7 0
3 years ago
Marcus observed that 8 of the 20 games that he had bowled last week were over 180. What percent of his games were over 180?
shepuryov [24]

Answer:

40%

Step-by-step explanation:

Ok so my brain is sorta not working but it said "hey! 20 divided by 2 is 10!"

So I was like ight and divided 80 by 2 to to get 40%.

Hope this helps.

6 0
2 years ago
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