The pair of numbers that would have 20 as their lcm is 4 and 5
Answer:
Step-by-step explanation:
Total = 50
Males = 20
Females = 30
a) P(exactly 1 female) = P(1 female , 2 male)
(30C1 * 20C2) / (50C3) = 30*190/19,600 = 0.2908
b) P(at least 2 males) = 1 - (P(0 males) + P(1 males))
= 1 - 30C3 * 20C0/50C3 - 30C2 * 20C1/50C3
= 1 - 4060*1/19,600 - 435*20/19,600 = 6840/19600 = 0.3489
Answer:
r5 tj rhe 62hs fgus us reallh bard lil
