Answer:
Down below
Step-by-step explanation:
a. The range of y = sinθ is [-1,1]
b. The period of y = cosθ is 2π
c. The asymptotes of y = tanθ are -π2, π2, πn
d. The amplitude of y = sinθ is 1
e. The period of y = tanθ is π
f. The max value of y = cosθ is 1
Answer:
0.675 m/s
Step-by-step explanation:
Let height of shadow= y,CD=x
Height of man=2 m
Speed of man= 
Therefore, 
Differentiate w.r.t t
When the man is 4 m from the building
Then, we have x=12-4=8 m
Substitute the values in above equation then, we get
Substitute the values then we get
Hence, the length of his shadow on the building decreasing at the rate 0.675 m/s.
DEF= 6 ft^2
A= 1/2*b*h
Plug in what you know.
6= 1/2*4*h
Multiply like terms.
6=2*h
Divide 2 on both sides.
3=h
If the base of ABC= 12
12/4=3
3*3=9
A= 1/2*b*h
A= 1/2*12*9
A= 1/2*84
A= 42
The area of ABC is 42 ft^2
I hope this helps!
~kaikers
Answer:
$10,000
Step-by-step explanation:
-12,000+23,200-1,200= 10,000
Answer:
f(x)=11+7√x
f'(x)=7/(2x^(1/2))
putting x=1
f'(1) = 7/(2×1^(1/2))
= 7/2 = 3.5
putting x=2
f'(2) = 7/(2×2^(1/2))
= 7/(2×√2)
= 7√2/4
= 2.47 (rounded to the nearest hundredth)
f'(3) = 7/(2×3^(1/2))
= 7/(2×√3)
= 7√3/6
= 2.02 (rounded to the nearest hundredth)
