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ikadub [295]
3 years ago
6

a pharmacy put 4.536 oz of vitamin pills into a bottle she put 0.042 oz of vitamin pills into each bottle how many bottles did t

he pharmacy use for these vitamin pills
Mathematics
1 answer:
MrRissso [65]3 years ago
5 0

Answer:

108 bottles

Step-by-step explanation:

the total is 4.536 oz of vitamin pills

each bottle can accomodate 0.042 oz of vitamin pills

to know the quantity of each bottle

we calculate

0.042 oz of vitamin pills  = 1 bottle

4.536 oz of vitamin pills = (4.536 x 1)/0.042=108

so therefore 4.536 oz of vitamin pills will accomodate 108 bottles

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The table below represents a proportional relationship. The unit rate of the relationship is
jek_recluse [69]

Answer:

the unit rate is 3

7 0
3 years ago
Factor.<br><br> 9x2−25y2<br><br> Enter your answer in the boxes.<br> (<br> )(
Anettt [7]

Answer:

( 3x + 5y) • (3x - 5y)

Step-by-step explanation:

hope this helps:))

3 0
3 years ago
The length of a rectangle is twice the with. If the perimeter of the rectangle is 60 units, find the area of the garden
Darya [45]

w - width

2w - length

60 - perimeter

w + w + 2w + 2w = 6w - perimeter

The equation:

6w = 60    <em>divide both sides by 6</em>

w = 10 → 2w = 2 · 10 = 20

The area: A = width × length

A = (10)(20) = 200

<h3>Answer: The area of the garden is equal 200 square units.</h3>
4 0
3 years ago
Suppose that an airline uses a seat width of 16.5 in. Assume men have hip breadths that are normally distributed with a mean of
Alexxx [7]

Answer:

a) 0.018

b) 0            

Step-by-step explanation:

We are given the following information in the question:

Mean, μ =  14.4 in

Standard Deviation, σ = 1 in

We are given that the distribution of breadths is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(breadth will be greater than 16.5 in)

P(x > 16.5)

P( x > 16.5) = P( z > \displaystyle\frac{16.5 - 14.4}{1}) = P(z > 2.1)

= 1 - P(z \leq 2.1)

Calculation the value from standard normal z table, we have,  

P(x > 16.5) = 1 - 0.982 = 0.018 = 1.8\%

0.018 is the probability that if an individual man is randomly​ selected, his hip breadth will be greater than 16.5 in.

b) P( with 123 randomly selected​ men, these men have a mean hip breadth greater than 16.5 in)

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}  

P(x > 16.5)  

P( x > 16.5) = P( z > \displaystyle\frac{16.5-14.4}{\frac{1}{\sqrt{123}}}) = P(z > 23.29)  

= 1 - P(z \leq 23.29)

Calculation the value from standard normal z table, we have,  

P(x > 16.5) = 1 - 1 = 0

There is 0 probability that 123 randomly selected men have a mean hip breadth greater than 16.5 in

4 0
3 years ago
Solve the system of equations. x=-2y+1 and x+2y=9. PLEASE SHOW WORK
docker41 [41]

Answer:

N0 solution.

Step-by-step explanation:

x=-2y+1....(1)

x+2y=9....(2)

put equation (2) to equation (1)

-2y+1 + 2y=9

combine

-2y + 2y=9-1

0=8

No solution.

4 0
3 years ago
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