The table below represents a proportional relationship. The unit rate of the relationship is

HELPPPP If y=4, 3y+6=7(2y-3)

Step2247 [10]

Answer:

i think your question is missing something??

Step-by-step explanation:

3(4) + 6 = 7 (2(4)-3)

12 + 6 = 7 (8-3)

18 = 7 (5)

18 = 35?

8 0

3 years ago

Solve for x. Show your work with proper statements and notation.

9966 [12]

Answer:

x = 26

Step-by-step explanation:

The sum of the angles around point O = 360°, thus

x + 3x + 256 = 360 , that is

4x + 256 = 360 ( subtract 256 from both sides )

4x = 104 ( divide both sides by 4 )

x = 26

4 0

3 years ago

A builder wants to build the bridge whose cross section is shown in the diagram. Two companies offer simple bids on building the

leva [86]

The length of the bridge is the distance from the beginning to the end.

The distance b between each beam is 9ft.

Let:

$I \to$ I-Beam

$d_I \to$ distance between I beam and the bridge

$b \to$ distance between each I beam

Given that:

$I = \frac 34 ft\\$

$d_I = 3 ft$

$Length = 55ft\ 6in$ --- length of the bridge

From the diagram (see attachment), there are: 6 I-beams.

So, the length of the 6 I-beams is:

$L_1 = 6 \times I$

$L_1 = 6 \times \frac 34$

$L_1 = \frac {18}4$

$L_1 = 4.5ft$

There are 2 I-beams beside the bridge

So, the distance between the 2 I-beams and the bridge is:

$d_1 =2 \times d_I$

$d_1 =2 \times 3ft$

$d_1 =6ft$

There are 5 spaces between the I-beams

So, the length of the total spaces is:

$L_2 = 5 \times b$

$L_2 = 5b$

The total length is:

$Length = L_1 + d_1 + L_2$

So, we have:

$4.5ft + 6ft + 5b = 55ft\ 6in$

Collect like terms

$5b = 55ft\ 6in - 4.5ft - 6ft$

$5b = 44.5ft\ 6in$

Convert inches to feet

$5b = 44.5ft\ + \frac{6}{12}ft$

$5b = 44.5ft\ + 0.5ft$

$5b = 45ft$

Divide both sides by 5

$b = 9ft$

Hence, the distance (b) between each beam is 9ft.

Read more about lengths at:

brainly.com/question/22059747

3 0

2 years ago

What is the slope of this graph?

SVEN [57.7K]

I think you might’ve forgotten to insert a picture? Feel free to reply to this with the picture of the question and I’ll do my best to help you out :)

8 0

3 years ago

Read 2 more answers

The ratio of boys to girls in the entire 6th grade is 3 to 2. Given this ratio, which two class compositions are possible?

gtnhenbr [62]

Answer:

There's an infinite number of possible answers because there might be any multiplication of 3 for boys and any multiplication of 2 for girls. So, for example:

There might be 3 boys and 2 girls.

There might be 6 boys and 4 girls.

There might be 9 boys and 6 girls.

There might be 12 boys and 8 girls.

etc...

In each case the ratio stays the same - 3 : 2.

Of course there probably can't be more than a few dozens of people in one class, but theoretically we can raise the numbers up to infinite.

Step-by-step explanation:hope this help.

7 0

2 years ago