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aksik [14]
3 years ago
10

The table below represents a proportional relationship. The unit rate of the relationship is

Mathematics
1 answer:
jek_recluse [69]3 years ago
7 0

Answer:

the unit rate is 3

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Find the values of x (if any) at which f(x)= x+1/x2-1 is not continuous. If so, is the discontinuity removable?
SIZIF [17.4K]

Answer:

d. none of these

Step-by-step explanation:

i think

8 0
3 years ago
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Svet_ta [14]

Answer:

$35 for each sweater

Step-by-step explanation:

First subtract the skirt $160 - $20 = $140

Then Divide to find cost of each sweater $140/4 = 35

Answer: 35

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3 years ago
Cut 9ft piece into 12inch & Every cut remove 1/8 inch
melamori03 [73]
So each foot is 12 inches so to remove 8 feet to get 12 in you need to remove 8 times 12 inches total or 96 in and each cut removes 1/8 in so times 96 by 8 and get 768 total cuts
6 0
3 years ago
Type the correct answer in each box. (____)
trapecia [35]

Answer:

1. -16; 2. +64; 3. 16

Step-by-step explanation:

The formula for the volume of a cylinder is

V = πr²x

Data:

r = (x - 8)   mm

V = 1024π mm³

Calculations:

1. Find the cubic equation  

V = πr²h

1024π = π(x - 8)² × x

Divide each side by π

1024 = x(x - 8)²  

1024 = x(x² - 16x  + 64)

1024 =    x³ - 16x² + 64x

x³ - 16x² + 64x - 1024 = 0

2. Solve the cubic equation

The general formula for a third-degree polynomial is

f(x) = ax³ + bx² + cx + d

Your polynomial is  

f(x) = x³ - 16x² + 64x - 1024

a = 1; d = -1024

According to the <em>rational roots theorem</em>, the possible roots are

factors of d/factors of a

Factors of d = ±1, ±2, ±4, ±8, ±16, ± 32, ± 64, ±128, ±256, ±512, ±1024

Factors of a = ±1

Potential roots are x = ±1, ±2, ±4, ±8, ±16, ± 32, ± 64, ±128, ±256, ±512, ±1024

That's a lot of possibilities to check by trial and error. I will just use the one that works.

Try x = 16 by synthetic division.

16|1  -16   64  -1024

  <u>|     16     0   1024 </u>

   1     0   64        0

So,

(x³ - 16x² + 64x - 1024)/(x – 16) = x² + 64

and

(x - 16)(x² + 64) = 0

x - 16 = 0        x² + 64 =    0

     x = 16       x²         = -64

                       x          =  ±8i

There is only one real root: x = 16 mm

6 0
3 years ago
When y=_7, find the value of 2y2- 9
topjm [15]

2x(-7)^2-9 = 2x49-9=98-9=89 maybe

7 0
2 years ago
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