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12345 [234]
4 years ago
10

How to do this question plz answer me step by step plzz ​

Mathematics
1 answer:
Molodets [167]4 years ago
7 0

Answer:

120 degrees. Hope this helps

<3

Step-by-step explanation:

We know the sum of all the angles in a quadilateral is equal to 360. so,

it would be: 360 - (55+65+120)

= 360 - 240

= 120 degrees

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The fraction 5/3 has what as the denominator
Lyrx [107]

Answer:3

Step-by-step explanation:

6 0
3 years ago
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what is the probability of randomly selecting a black marble from the bag with 4 white, 4 black, and 2 striped
NARA [144]

Answer:

4/10 or 40%

Step-by-step explanation:

4 black marbles out of 10 which equals to 4/10

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4 years ago
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Help me please for my final
Vadim26 [7]

Answer:

Equation of line l,

3x-4y=1/2

y=3/4x-1/2

we get,

slope of line l =3/4

Equation of line m,

x-5=2y

y=1/2-5/2

Hence slope of line m=1/2

Slope of line l is not equal to slope of line m. Hence the line are not parallel.

Slope of line l* slope of line m ,

(3/4)*(1/2) =3/8

Since the product of slope of line l and the slope of line m is not equal to -1, the lines are not perpendicular.

Hence the lines are neither perpendicular nor parallel..

5 0
3 years ago
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What is the least perfect square which is divisible by 24 30 and 60?
yanalaym [24]

Step 1: LCM of 24 , 30 and 60 = 120

so 120 is the least no which is divisible by all 24 , 30 and 60

Step 2: factors of 120 will be 2^3 * 3 * 5

so the least perfect square, which is divisible by 24, 30 and 60 will be
(2^3 * 3 * 5) x ( 2 * 3 * 5 ) = 3600



3600
6 0
3 years ago
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Find the absolute maximum and minimum values of f(x,y)=xy−4x in the region bounded by the x-axis and the parabola y=16−x2.
skad [1K]

Answer:

The absolute maximum and minimum is 20\; \text{and} -20.

Step-by-step explanation:

We first check the critical points on the interior of the domain using the

first derivative test.

f_x=y-4=0

f_y=x=0

The only solution to this system of equations is the point (0, 4), which lies in the domain.

f_{xx}=0, \;f_{yy}=0\; \text{and}\; f_{xy}=-1

\Rightarrow f_{xx}f_{yy}-f_{xy}=o-1=-1

\therefore (0,4) is a saddle point.

Boundary points -  (4,0),  (-4,0), (0,16)

Along boundary  y=16-x^2

   f=x(16-x^2)-4x

=16x-x^3-4x

\Rightarrow f^'=16-3x^2-4=0

\Rightarrow 3x^2=12

\Rightarrow x=\pm2,\;\;y=14

Values of f(x) at these points.

\begin{array}{}(4,0)=-16\\(-4,0)=16\\(0,16)=0\\(2,14)=20\\(-2,14)=-20\end{array}

Therefore, the absolute maximum and minimum is 20\; \text{and} -20.

6 0
4 years ago
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