All categories

2 years ago

Help me please for my final

Mathematics

2 answers:

Vadim26 [7]2 years ago

5 0

Answer:

Equation of line l,

3x-4y=1/2

y=3/4x-1/2

we get,

slope of line l =3/4

Equation of line m,

x-5=2y

y=1/2-5/2

Hence slope of line m=1/2

Slope of line l is not equal to slope of line m. Hence the line are not parallel.

Slope of line l* slope of line m ,

(3/4)*(1/2) =3/8

Since the product of slope of line l and the slope of line m is not equal to -1, the lines are not perpendicular.

Hence the lines are neither perpendicular nor parallel..

LUCKY_DIMON [66]2 years ago

4 0

Answer:

none are parallel

Step-by-step explanation:

You might be interested in

A. > B. < C. = D. none of the above

earnstyle [38]

Answer:

$3.14 \times 10 ^{3} < 2.6 \times 10^{3}$

Step-by-step explanation:

$3.14 \times 10 ^{3}$

$3140$

$2.6 \times 10 ^{4}$

$26000$

7 0

2 years ago

What is equivalent to 2 5/6 A) 12/5 B) 17/6 C) 5/3 D) 7/6

KatRina [158]

B) 17/6

First I multiply 2 times 6 which gave me 12 then I added 12 plus 5 which gave me 17 then I used the number at the bottom which is 6 so the final answer was 17/6

5 0

3 years ago

What is the sum of all integers between 123 and 2021 which end in 7? Please walk me through it w/ work.

Savatey [412]

Answer:

it will be 35720 . I hope my answer is correct

6 0

2 years ago

A town is designing a rectangular park that will be 600 feet by 1000 feet. A rectangular area of the park for swing sets will be

drek231 [11]

Scale factor = 0.5 / 25 = 0.02 inches per foot

on scale drawing of the park the dimensuons will be 600 * 0.02 by 1000*0.02
= 12 inches by 20 inches

8 0

3 years ago

Read 2 more answers

At which values of x does the function F(x) have a vertical asymptote? Check all that apply. F(x)=2/3x(x-1)(x 5).

Alekssandra [29.7K]

The function F(x) have a vertical asymptote at x =0 and x =1.

Given that

The given Function;

$\rm F(x)=\dfrac{2}{3x(x-1)(x^ 5)}$

We have to determine

At which value the function F(x) has a vertical asymptote.

According to the question

The given Function;

$\rm F(x)=\dfrac{2}{3x(x-1)(x^ 5)}$

The function is undefined when the denominator becomes 0. Find values of x for which the denominator is 0:

Then,

$\rm 3x (x-1) (x^5)= 0$

$\rm x^5 =0, \ \ x=0\\\\ x-1 = 0, \ \ x =1\\$

The value of x is 0 and 1.

Hence, the function F(x) have a vertical asymptote at x =0 and x =1.

To know more about Parabola click the link given below.

brainly.com/question/12868913

7 0

2 years ago