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maria [59]
3 years ago
8

The probability that Maria succeeds at any given free-throw is 75\%75%75, percent. She was curious how many free-throws she can

expect to succeed in a sample of 101010 free-throws. She simulated 252525 samples of 101010 free-throws where each free-throw had a 0.750.750, point, 75 probability of being a success. Maria counted how many free-throws were successes in each simulated sample. Here are her results: Use her results to estimate the probability that she succeeds at fewer than 777 free-throws in a sample of 101010 free-throws.
Mathematics
2 answers:
mestny [16]3 years ago
7 0

Answer:

25/5= 5/1 =0.2

Step-by-step explanation:

Fivestart color #7854ab, start text, F, i, v, e, end text, end color #7854ab of the 252525 simulated samples had fewer than 777 successful free-throws.

sdas [7]3 years ago
5 0

Answer:

.2

Step-by-step explanation:

5/25

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