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3 years ago

Find the midpoint between the two points (-4,4) and (-2,2)

Mathematics

1 answer:

Ymorist [56]3 years ago

6 0

Answer: (-3,3) is the answer

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Regroup hundreds as Tens:<br><br> 8 hundreds 9 tens =

Lilit [14]

89 tens because 8 x10 is 80 add the 9
89

7 0

3 years ago

Please help me with 10

romanna [79]

Answer:

yes the answer is he does make sense

3 0

2 years ago

A coordinate plane with a line passing through the points (negative 4, negative 5) and (1, negative 1).

Ksju [112]

Answer:

4x - 5y - 9 = 0

$\frac{9}{4}$

$\frac{-9}{5}$

Step-by-step explanation:

The equation of a straight line passing through the points (-4,-5) and (1,-1) is given by $\frac{y - (-5)}{-5-(-1)} =\frac{x-(-4)}{-4-1}$

⇒ $\frac{y+5}{-4} =\frac{x+4}{-5}$

⇒ 5y + 25 = 4x + 16

⇒ 4x - 5y - 9 = 0 ....(1) (Answer)

Now, this above equation can be represented as

$\frac{x}{\frac{9}{4} } + \frac{y}{\frac{-9}{5} } =1$

Therefore, the x-intercept is $\frac{9}{4}$ (Answer)

And the y-intercept is $\frac{-9}{5}$ . (Answer)

7 0

3 years ago

Read 2 more answers

Please help me!! i don’t understand this like at all this is algebra btw

gladu [14]

The length and width of the fence should be made 76.25 feet and 23.75 feet respectively. Also, the expression for the length is L = 3W + 5 and the perimeter is P = 2(4W + 5).

<h3>How to determine the fence's dimension?</h3>

Mathematically, the perimeter of a rectangle can be calculated by using this formula;

P = 2(L + W)

<u>Where:</u>

P is the perimeter of a rectangle.

L is the length of a rectangle.

W is the width of a rectangle.

Since the length of this fence is 5 more than 3 times the width, we have:

L = 3W + 5

Substituting the given parameters into the formula, we have;

200 = 2(3W + 5 + W)

200 = 2(4W + 5)

200 = 8W + 10

8W = 190

W = 190/8

W = 23.75 feet.

For the length, we have:

L = 3W + 5

L = 3(23.75) + 5

L = 76.25 feet.

Read more on perimeter of a rectangle here: brainly.com/question/17107023

#SPJ1

5 0

1 year ago

The capacity of an elevator is 12 people or 2088 pounds. the capacity will be exceeded if 12 people have weights with a mean gre

boyakko [2]

suppose the people have weights that are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.

Find the probability that if a person is randomly selected, his weight will be greater than 174 pounds?

Assume that weights of people are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.

Mean = 177

standard deviation = 26

We find z-score using given mean and standard deviation

z = $\frac{x-mean}{standard deviation}$

= $\frac{174-177}{26}$

=-0.11538

Probability (z>-0.11538) = 1 - 0.4562 (use normal distribution table)

= 0.5438

P(weight will be greater than 174 lb) = 0.5438

8 0

3 years ago