Answer:
so many bots have replied to my questions :\\\
Step-by-step explanation:
The answer would be D, not sure if you still need it.
Answer:
(c) (12th root of 8)^x
Step-by-step explanation:
The applicable rules of exponents are ...
![(a^b)^c=a^{bc}\\\\\sqrt[n]{a}=a^{1 \! /n}](https://tex.z-dn.net/?f=%28a%5Eb%29%5Ec%3Da%5E%7Bbc%7D%5C%5C%5C%5C%5Csqrt%5Bn%5D%7Ba%7D%3Da%5E%7B1%20%5C%21%20%2Fn%7D)
In this case, we have ...
![(\sqrt[3]{8})^{x/4}=8^{1/3\cdot x/4}=8^{x/12}=\boxed{\left(\!\sqrt[12]{8}\right)^x}](https://tex.z-dn.net/?f=%28%5Csqrt%5B3%5D%7B8%7D%29%5E%7Bx%2F4%7D%3D8%5E%7B1%2F3%5Ccdot%20x%2F4%7D%3D8%5E%7Bx%2F12%7D%3D%5Cboxed%7B%5Cleft%28%5C%21%5Csqrt%5B12%5D%7B8%7D%5Cright%29%5Ex%7D)
Answer:
6 ± i and 6 ± i
Step-by-step explanation:
Let x be the first number.
Let y be the second number.
x + y = 12
x × y = 37
Solve for x in the first equation.
x = 12 - y
Put x as 12-y in the second equation and solve for y.
(12- y)y = 37
12y - y² = 37
- y² + 12y - 37 = 0
y = 6 ± i
Put y as 6 ± i in the first equation and solve for x.
x + 6 ± i = 12
x = 12 - 6 ± i
x = 6 ± i
