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zloy xaker [14]
3 years ago
11

If the lengths of two sides of a right triangle are 5 and 12 units, what is the least possible length, in units, of the third si

de? Express your answer in simplest radical form.
Mathematics
2 answers:
miskamm [114]3 years ago
6 0

Answer:

13

Step-by-step explanation:

timofeeve [1]3 years ago
3 0

(leg)^2 + (leg)^2 = (hypotenuse)^2

(5)^2 + (12)^2 = (h)^2

25 + 144 = (h)^2

169 = (h)^2

sqrt{169} = sqrt{(h)^2}

-13 = h

13 = h

We reject h = -13 because length is a distance and distance cannot be negative.

So, h = 13 units is the answer.

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The sum of three consecutive even numbers is 66. What is the smallest of these numbers?​
maw [93]

Answer:

20

Step-by-step explanation:

one way is guess and check method, you draw a table and try out 3 different consecutive even numbers to see which 3 add up to 66

7 0
3 years ago
7metros mas 9.40 metros​
Tresset [83]

Answer:

I don't know

Step-by-step explanation:

4 0
3 years ago
Please Answer ASAP
Masteriza [31]

hence, the common ratio of the given G.P. is 3 or −3.

6 0
3 years ago
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Please help answer these questions. My teacher said they were really easy but I just don't understand. Will mark brainliest !!!
kodGreya [7K]

Answer:

1.  A = 59

2.  A = 43

Step-by-step explanation:

If we have a right triangle  we can use sin, cos and tan.

sin = opp/ hypotenuse

cos= adjacent/ hypotenuse

tan = opposite/ adjacent


For the first problem, we know the opposite and adjacent sides to angle A

tan A = opposite/ adjacent

tan A = 8.8 / 5.2

Take the inverse of each side

tan ^-1 tan A = tan ^-1 (8.8/5.2)

A = 59.42077313

To the nearest degree

A = 59 degrees


For the second problem, we know the  adjacent side and the hypotenuse to angle A

cos A = adjacent/hypotenuse

cos A = 15.3/21

Take the inverse of each side

cos ^-1 cos A = cos ^-1 (15.3/21)

A = 43.23323481

To the nearest degree

A = 43 degrees


6 0
3 years ago
Plz help pretty easy
cricket20 [7]

a and d b and c that's the answer

4 0
3 years ago
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