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GarryVolchara [31]
3 years ago
15

Given that (x+2) is a factor of x^3+8, find the other quadratic factor.

Mathematics
1 answer:
Semmy [17]3 years ago
3 0
If you know the formular a^3+b^3=(a+b)(a^2-ab+b^2), you can solve this problem.
8 is 2 cubed, so x^3+2^3=(x+2)(x^2-2x+4)
so the other quadratic factor is x^2-2x+4
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Hey there!!

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z + 6 = 4/3

z = 4/3 - 6

z = 4 - 18 / 3

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Hope it helps!

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2 years ago
The common ratio in a geometric series is 0.50.50, point, 5 and the first term is 256256256.
V125BC [204]

Answer:

504

Step-by-step explanation:

I think the correct question is like:The common ratio in a geometric series is 0.50 ( point 5) and the first term is 256.  

Find the sum of the first 6 terms in the series.

If it's right, then

Sₙ = (a₁ * (1 - rⁿ)) / (1 - r)

S₆ = (256 * ( 1 - 0.5⁶)) / (1 - 0.5) = (256 * 0.984375) / 0.5 = 504

6 0
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