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2 years ago

Given that (x+2) is a factor of x^3+8, find the other quadratic factor.

Mathematics

1 answer:

Semmy [17]2 years ago

3 0

If you know the formular a^3+b^3=(a+b)(a^2-ab+b^2), you can solve this problem.
8 is 2 cubed, so x^3+2^3=(x+2)(x^2-2x+4)
so the other quadratic factor is x^2-2x+4

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3 years ago

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djyliett [7]

Answer:

210 + -1x

Step-by-step explanation:

Simplifying

X + (x + -30) = 180

Reorder the terms:

X + (-30 + x) = 180

Remove parenthesis around (-30 + x)

X + -30 + x = 180

Reorder the terms:

-30 + X + x = 180

Solving

-30 + X + x = 180

Solving for variable 'X'.

Move all terms containing X to the left, all other terms to the right.

Add '30' to each side of the equation.

-30 + X + 30 + x = 180 + 30

Reorder the terms:

-30 + 30 + X + x = 180 + 30

Combine like terms: -30 + 30 = 0

0 + X + x = 180 + 30

X + x = 180 + 30

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Add '-1x' to each side of the equation.

X + x + -1x = 210 + -1x

Combine like terms: x + -1x = 0

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Simplifying

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