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GarryVolchara [31]
3 years ago
15

Given that (x+2) is a factor of x^3+8, find the other quadratic factor.

Mathematics
1 answer:
Semmy [17]3 years ago
3 0
If you know the formular a^3+b^3=(a+b)(a^2-ab+b^2), you can solve this problem.
8 is 2 cubed, so x^3+2^3=(x+2)(x^2-2x+4)
so the other quadratic factor is x^2-2x+4
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In the given diagram , TY is a tangent to the circle TVS . If <SVT = 48° and |VS| = |ST| . What is < VTY.​
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