Answer: It goes to the ribosome for translation to occur. The ribosome is located in the cytoplasm.
Both parents' genotypes are Bb (brown blue)
the punnet square would be
BB(kid one) Bb(kid two) Bb(kid three) bb(kid four)
kid one will be homozygous for brown eyes. kid two and three will be heterozygous for brown eyes. kid four will be homozygous for blue eyes
in other words, 75% will have brown eyes. 25% will have blue eyes
Answer:
DNA is made up of six smaller molecules -- a five carbon sugar called deoxyribose, a phosphate molecule and four different nitrogenous bases (adenine, thymine, cytosine and guanine)
Explanation:
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<span>In Drosophila + indicates wild-type allele for any gene, m is mahogany and e is ebony.
Female parents are m+/m+ and males are +e/+e.
F1 are m+/+e, all wild type. F1 females are crossed with me/me males - the test cross.
Offspring will be : non recombinant m+/me, mahogany wild type or +e/me wild type ebony. OR
recombinant me/me mahogany ebony or ++/++ wild type.
As the two genes are 25 map units apart, the percentage of recombinants will be 25% and therefore percentage parental types will be 75%.
75% 1000 is 750. There are two parental types, so you would expect 375 of each. Therefore, you would expect 375 m+/me and 375 +e/me.
25% of 1000 is 250 split between two recombinants =125 of each. Therefore you would expect 135 me/me and 125 ++/++</span>
Answer:
the the climax of the night
