Answer:
Que estas como por que nada
Step-by-step explanation:
buenos nochas
The two number would be 3.5 and 8.5
To determine the 'intervals of increase' and 'intervals of decrease' we can refer to the graph with respect to the x - axis.
• Knowing that t = x - axis, the 'intervals of increase' as an inequality would be 1 < x < 3, and 4 < x < ∞. Therefore we have our intervals of increase as (1,3) and (4, ∞).
• Respectively our 'intervals of decrease' as inequalities would be - ∞ < x < 1, and 3 < x < 4. Our intervals of decrease would then be (- ∞, 1) and (3,4).
• We are left with our local extrema and absolute extrema. Now remember the absolute extrema is the absolute lowest point in the whole graph, while the local extrema is the lowest point in a restricted interval. In this case our local extrema is our maximum, (3,1). But this maximum is not greater than the starting point (0, 4) so it appears, and hence their is no absolute extrema.
Answer:
x is 6
Step-by-step explanation:
Answer:
Step-by-step explanation:
a)
p(d) - probability of a rivet being defective
p(r) - probability of seam needing to be reworked
The probability of the seem needing to be reworked is equal to the probability that ANY of 24 rivets is defective
Thus the probability that none of the 25 rivets is defective is 1-p(r)
p(r) = 16%, thus 1-p(r) = 84%
1-p(r) = (1-p(d))^24
0.84 = (1-p(d))^24
0.84^(1/24) = 1-p(d)
==> 1-p(d) = 0.9927615998
==> p(d) = 1-0.9927
==> p(d) = 0.0073
b) given p(r) = 8%, thus 1-p(r) = 92%
1-p(r) = (1-p(d))^24
0.92 = (1-p(d))^24
0.92^(1/24) = 1-p(d)
==> 1-p(d) = 0.99653179446
==> p(d) = 1-0.9965
==> p(d) = 0.0035