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finlep [7]
3 years ago
8

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Mathematics
2 answers:
ANTONII [103]3 years ago
8 0
(x²+4x-12)/(x-2)=0
(x+6)(x-2)/(x-2)=0
x+6=0
x=-6
(-6,0)
riadik2000 [5.3K]3 years ago
6 0

Answer:   (2, 8)

<u>Step-by-step explanation:</u>

f(x)=\dfrac{x^2+4x-12}{x-2}\\\\.\quad=\dfrac{(x+6)(x-2)}{(x-2)}\\\\\text{The denominator cannot equal zero so x - 2}\neq 0\ \rightarrow\ x\neq 2\\\text{Since, (x-2) can be canceled out, there is a hole at x = 2}\\\\f(x)=x+6\\f(2)=2+6\\.\ \ \quad =8\\\\\text{So, the coordinate of the hole is:}\ (2, 8)

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Hi what is the answer for this?
saw5 [17]
This is a common factor problem.

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First, break the number into their prime factors(the idea is that we will break the number down into its smallest multiples, which are prime numbers):
10 = 2 * 5
12 = 2 * 2 *3

So now we take the unique multiples of each number, and when we multiply them together, we will get the smallest number that both 10 and 12 can be divided into(this is what the problem is asking for)
We have (2*2*3) that comes from 12, and the only unique number that comes from the 10 is (5)
So now, we multiply:
2*2*3*5=60
However, this isn't exactly out answer. Now we have to divide our answer by the number of each this in the pack to know how many packs to buy.
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5 0
3 years ago
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2 years ago
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3 years ago
What is the simplified form of the following expression? 5√8-√18-2√2
Romashka [77]

Answer:

Option (B) is correct.

To prove

As given the epression in the question is given by

= 5\sqrt{8} - \sqrt{18} - 2 \sqrt{2}

Now simplify the above

Terms are written as

\sqrt{8} = \sqrt{2\times 2\times 2} = 2 \sqrt{2}

\sqrt{18} = \sqrt{3\times 3\times 2} = 3 \sqrt{2}

Put in the above expression.

= 5\times 2 \sqrt{2} -3 \sqrt{2} - 2 \sqrt{2}

= 10 \sqrt{2} -5 \sqrt{2}

=5 \sqrt{2}

Therefore\ the\ expression\ 5\sqrt{8} - \sqrt{18} - 2 \sqrt{2}\ is\ equivalent\ to\ 5 \sqrt{2} .





6 0
3 years ago
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Artyom0805 [142]
A-2b=-10
b=-10-a.
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