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Mathematics

2 answers:

ANTONII [103]3 years ago

8 0

(x²+4x-12)/(x-2)=0
(x+6)(x-2)/(x-2)=0
x+6=0
x=-6
(-6,0)

riadik2000 [5.3K]3 years ago

6 0

Answer: (2, 8)

<u>Step-by-step explanation:</u>

$f(x)=\dfrac{x^2+4x-12}{x-2}\\\\.\quad=\dfrac{(x+6)(x-2)}{(x-2)}\\\\\text{The denominator cannot equal zero so x - 2}\neq 0\ \rightarrow\ x\neq 2\\\text{Since, (x-2) can be canceled out, there is a hole at x = 2}\\\\f(x)=x+6\\f(2)=2+6\\.\ \ \quad =8\\\\\text{So, the coordinate of the hole is:}\ (2, 8)$

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