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horsena [70]
3 years ago
15

How many solutions does this equation have? –10q = –10q − 7

Mathematics
1 answer:
Salsk061 [2.6K]3 years ago
8 0

Answer:

None (no solutions)

Step-by-step explanation:

-10q=-10q-7 (add 10q to both sides to get the costant 7 by itself)

-10q+10q=-10q+10q-7

0=-7 ( zero will never equal -7 hence there are no solutions to this equation)

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What's 43080700 in word form
skad [1K]
Forty three million, eighty thousand seven hundred
8 0
3 years ago
What is the sign of the product (3) × (−3) × (−2) × (4)?
Free_Kalibri [48]

Answer:

Positive, because the products (3) × (−3) and (−2) × (4) are negative and the product of two negative numbers is positive.

Step-by-step explanation:

Since 1 * -1 = -1, and -1 * -1 = 1, the product of opposite signs produces negative numbers while the product of same signs produces positive numbers. So the product of 1 * 1 * 1 * -1 = -1, while -1 * -1 * -1 * -1 = 1.

3 0
3 years ago
Suppose f is a function. If 10 = f(-4), find the coordinates of a point on the graph of f?
Rashid [163]

Given:

For a function f, 10 = f(-4).

To find:

The coordinates of a point on the graph of f.

Solution:

We have,

10 = f(-4)

It means the value of function f is 10 at -4.

On a coordinate plane x-axis represents the input values and y-axis represents the output values of a function. So,

x-coordinate = input value = -4

y-coordinate = output value = 10

Therefore, the required coordinates of a point on the graph of f are (-4,10).

5 0
4 years ago
Solve the given equation. (Enter your answers as a comma-separated list. Let k be any integer. Round terms to two decimal places
Leya [2.2K]

Answer:

  θ = {(4/3 +2k)π, (5/3 +2k)π}

Step-by-step explanation:

From your knowledge of trig functions, you know that sin(60°) = sin(π/3) = (√3)/2. So, the angles of interest are in the 3rd- and 4th-quadrant and will have π/3 as their reference angle.

  θ = 4/3π +2kπ, and 5/3π +2kπ

7 0
3 years ago
A tank initially contains 60 gallons of brine, with 30 pounds of salt in solution. Pure water runs into the tank at 3 gallons pe
adoni [48]

Answer:

the amount of time until 23 pounds of salt remain in the tank is 0.088 minutes.

Step-by-step explanation:

The variation of the concentration of salt can be expressed as:

\frac{dC}{dt}=Ci*Qi-Co*Qo

being

C1: the concentration of salt in the inflow

Qi: the flow entering the tank

C2: the concentration leaving the tank (the same concentration that is in every part of the tank at that moment)

Qo: the flow going out of the tank.

With no salt in the inflow (C1=0), the equation can be reduced to

\frac{dC}{dt}=-Co*Qo

Rearranging the equation, it becomes

\frac{dC}{C}=-Qo*dt

Integrating both sides

\int\frac{dC}{C}=\int-Qo*dt\\ln(\abs{C})+x1=-Qo*t+x2\\ln(\abs{C})=-Qo*t+x\\C=exp^{-Qo*t+x}

It is known that the concentration at t=0 is 30 pounds in 60 gallons, so C(0) is 0.5 pounds/gallon.

C(0)=exp^{-Qo*0+x}=0.5\\exp^{x} =0.5\\x=ln(0.5)=-0.693\\

The final equation for the concentration of salt at any given time is

C=exp^{-3*t-0.693}

To answer how long it will be until there are 23 pounds of salt in the tank, we can use the last equation:

C=exp^{-3*t-0.693}\\(23/60)=exp^{-3*t-0.693}\\ln(23/60)=-3*t-0.693\\t=-\frac{ln(23/60)+0.693}{3}=-\frac{-0.959+0.693}{3}=  -\frac{-0.266}{3}=0.088

5 0
3 years ago
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