Ask question

Ask question

All categories

3 years ago

8

Frankie bought 13 yards of string for her art project. Each yard cost $2.00. Malika spent $54.00 on the string. How much more di

d malika spend on string than frankie

1 answer:

kirill115 [55]3 years ago

8 0

Step-by-step explanation:

13x+2=54

subtract 2 from both sides.

13x=54

divide both sides by 13

x=4.

therefore Malika spend 4 more dollars on a string than Frankie

You might be interested in

2.85 as a mixed number

Phoenix [80]

$2.85=2+0.85=2+ \frac{85}{100} =2+ \frac{5*17}{5*20} =2+ \frac{17}{20} =2\frac{17}{20}$

I hope you got the idea

3 0

2 years ago

Find x. Round to the nearest tenth if necessary.a 4 b 5 c 6 d 3

DiKsa [7]

The answer is B. 5

6+2=8

3+5=8

8 0

2 years ago

Find the commission.<br> Earning Commission | sales = $530 | commision rate = 3% | commision = ?

sergij07 [2.7K]

Answer:

$15. 90

Step-by-step explanation:

3% of 530= 15.9

4 0

2 years ago

Read 2 more answers

What is the product of <br>(7/8)(-16)(-7)(-1/14)<br><br>A -7<br>B -9/16<br>C -1/7<br>D 23/12

Nat2105 [25]

Answer:

-7

Step-by-step explanation:

(7/8)(-16)(-7)(-1/4)

(7/8)(-1/4)(-16)(-7)

(-1/16)(112)

-7

4 0

2 years ago

A ball is thrown into the air from a height of 4 feet at time t = 0. The function that models this situation is h(t) = -16t2 + 6

katrin2010 [14]

Answer:

Part a) The height of the ball after 3 seconds is $49\ ft$

Part b) The maximum height is 66 ft

Part c) The ball hit the ground for t=4 sec

Part d) The domain of the function that makes sense is the interval

[0,4]

Step-by-step explanation:

we have

$h(t)=-16t^{2} +63t+4$

Part a) What is the height of the ball after 3 seconds?

For t=3 sec

Substitute in the function and solve for h

$h(3)=-16(3)^{2} +63(3)+4=49\ ft$

Part b) What is the maximum height of the ball? Round to the nearest foot.

we know that

The maximum height of the ball is the vertex of the quadratic equation

so

Convert the function into a vertex form

$h(t)=-16t^{2} +63t+4$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$h(t)-4=-16t^{2} +63t$

Factor the leading coefficient

$h(t)-4=-16(t^{2} -(63/16)t)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$h(t)-4-16(63/32)^{2}=-16(t^{2} -(63/16)t+(63/32)^{2})$

$h(t)-(67,600/1,024)=-16(t^{2} -(63/16)t+(63/32)^{2})$

Rewrite as perfect squares

$h(t)-(67,600/1,024)=-16(t-(63/32))^{2}$

$h(t)=-16(t-(63/32))^{2}+(67,600/1,024)$

the vertex is the point (1.97,66.02)

therefore

The maximum height is 66 ft

Part c) When will the ball hit the ground?

we know that

The ball hit the ground when h(t)=0 (the x-intercepts of the function)

so

$h(t)=-16t^{2} +63t+4$

For h(t)=0

$0=-16t^{2} +63t+4$

using a graphing tool

The solution is t=4 sec

see the attached figure

Part d) What domain makes sense for the function?

The domain of the function that makes sense is the interval

[0,4]

All real numbers greater than or equal to 0 seconds and less than or equal to 4 seconds

Remember that the time can not be a negative number

6 0

2 years ago