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PSYCHO15rus [73]
3 years ago
10

What is the greatest common factor of the polynomial below?

Mathematics
1 answer:
grin007 [14]3 years ago
6 0

Answer:

2x.

Step-by-step explanation:

The GCF of 10 and 14 is 2,

and the GCF of x^3 and x is x.

The answer is 2x.

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Sophie Ruth is eating a
Firdavs [7]

Answer:

15 grams

Step-by-step explanation:

There is a 50 gram chocolate bar that contains 30% cocoa. So we are basically finding 30% of 50. We break 30 into 3*10 and 50 into 5*10. 5*3 = 15.

Therefore, there are 15 grams of cocoa in the chocolate bar.

I hope this helps.

6 0
3 years ago
The manufacturer of an energy drink spends $1.20 to make each drink and sells them for two dollars the manufacturer also has fix
dimulka [17.4K]

Let X be the number of energy drinks sold.

The manufacturer of an energy drink spends $1.20 to make each drink and sells them for two dollars the manufacturer also has fixed cost each month of $8000.

The manufacturing cost for X energy drinks is

1.20x

Fixed cost is $8000.

Therefore, cost function is

C(x)=1.20x+8000

Selling price of each drink is $2.

Therefore, the revenue function is

R(x)=2x

Hence, the revenue function is

R(x)=2x

6 0
1 year ago
What is 37.06 on ft to sq yrds
Anastaziya [24]
37.06 to yards is 

4.1177 Square yards

5 0
3 years ago
Read 2 more answers
Is this correct btw I put 1400​
Oxana [17]

Answer: Yes

Step-by-step explanation: The answer of 1400 is correct.

What I did is I found the area of the figure assuming it was a rectangle, then I subtracted the corners that were removed.

1800 - 150 - 100 - 150 = 1400

5 0
3 years ago
Read 2 more answers
I have no idea!! Please help!!!
Ber [7]
The area of a traingle is \frac{1}{2}bh
So we need to know the base and the height
To work out the sides of a right angle triangle we can use a²+b²=c
c is the hypotenuse and a and b are the other sides
Because this triangle is isoceles we know that a and b are the same

a²+b²=c²
a²+a²=c²
2a²=c²
2a²=(x√6)²
2a²=(x√6)(x√6)
2a²=x²+x√6+x√6+6
2a²=x²+x√6+x√6+6
a²=\frac{x^{2}+x \sqrt{6}+x \sqrt{6}+6 }{2}
a=\sqrt{\frac{x^{2}+x\sqrt{6}+x\sqrt{6}+6}{2}}

A=\frac{1}{2}bh
A=\frac{1}{2}a*a
A=\frac{1}{2}×\sqrt{\frac{x^{2}+x\sqrt{6}+x\sqrt{6}+6}{2}}×\sqrt{\frac{x^{2}+x\sqrt{6}+x\sqrt{6}+6}{2}}
A=\frac{1}{2}×\frac{x^{2}+x \sqrt{6}+x \sqrt{6}+6 }{2}
A=\frac{x^{2}+x \sqrt{6}+x \sqrt{6}+6 }{4}
8 0
3 years ago
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