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slamgirl [31]
3 years ago
12

Which fraction is equivalent to 7/15? A. 14/28 B. 14/17 C. 21/45 D. 21/35

Mathematics
2 answers:
jasenka [17]3 years ago
6 0
THe answer is C since you multiply the numerator and denominator by 3
Leto [7]3 years ago
5 0
C. 21/45

If you multiply both the 7 and 15 by 3, you get 21 and 45.

\frac{7}{15} ×  \frac{3}{3} =  \frac{21}{45}
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Murrr4er [49]

Answer:

20/45

Step-by-step explanation:

4/8 = 2/4 = 1/2  

4*3/8*3 = 12/24

but 20/45 = 4/9 So it is mot equivalent to 4/8

6 0
3 years ago
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A rectangular cake has a length of 13 1/2 inches and a width of 9 inches. How many whole, square pieces of cake with side length
aleksandr82 [10.1K]
Let’s find the area of the rectangular cake and the square pieces.
I’m going to turn the fractions into decimals since it’s easier for me.
13.5•9
121.5
Now find the area of the square pieces.
2.25•2.25
5.0625
Now divide the area of the cake by the pieces to find how many can fit.
121.5/5.0625
24
So, 24 square pieces can be cut out of the rectangular cake.
7 0
3 years ago
What is X-5+10x+3???
Alekssandra [29.7K]

Answer:

-2+11x

Step-by-step explanation:

Combine like terms

(-5+3)+(x+10x)

-5+3 = -2

x+10x = 11x

-2+11x

8 0
3 years ago
How to turn fractions into decimals
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7 0
3 years ago
The image of a triangle after it has been dilated with a center at the origin has vertices at A’(-12,6) B’(6,-18) and C’ if the
ArbitrLikvidat [17]

Answer:

  • scale factor is 2/3.
  • coordinates of B are (9,-27).
  • coordinates of C' are : (12,18)

Step-by-step explanation:

The image of a triangle after it has been dilated with a center at the origin has vertices at A’(-12,6) B’(6,-18) and C’ .

Point A has coordinates of (-18,9) and the pre- image of C' point C has coordinates of (18,12).

Clearly when we compare point A and point A' we see that the transformation is a dilation.

let the scale factor of dilation is 'k'.

i.e. A→ A'

i.e. k(-18,9)=(-12,6)

(-18k,9k)=(-12,6)

i.e. -18k=-12

and 9k=6

Hence, on solving we get:

k=2/3

i.e. the scale factor is 2/3.

Also,

we find the coordinates of B(c,d) by:

2/3(c,d)=(6,-18)  since B→ B'

2/3×c=6

Hence c=9

and 2/3 ×d=-18

d=-27.

Hence, the coordinates of B are (9,-27).

Also the coordinates of C are (18,12)

Hence, coordinates of C' are:

(\dfrac{2}{3}\times 18,\dfrac{3}{2}\times 12)\\\\=(12,18)

Hence, the coordinates of C' are : (12,18)

7 0
3 years ago
Read 2 more answers
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