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3 years ago

What is X-5+10x+3???

Mathematics

1 answer:

Alekssandra [29.7K]3 years ago

8 0

Answer:

-2+11x

Step-by-step explanation:

Combine like terms

(-5+3)+(x+10x)

-5+3 = -2

x+10x = 11x

-2+11x

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What is the relation between the trigonometric ratios tan(R) and tan(J)? Please answer ASAP!

Ilya [14]

Step-by-step explanation:

∆PQR similar to ∆ JKL

JK/KL= PQ/QR

6/12=3/QR

QR=3×2= 6

therefore, tan(R) = PQ/QR = 3/6=1/2

and, tan(J) = KL/JK =12/6=2

$\frac{ \tan(R) }{ \tan(J) } = \frac{ \frac{1}{2} }{2}$

$\frac{ \tan(R) }{ \tan(J) } = \frac{1}{4}$

tan(J)=4.tan(R)

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2 years ago

The diagram shows a triangle.

Basile [38]

Answer:

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Step-by-step explanation:

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2 years ago

Which recursive sequence produced sequence 6, -26, 102,

LekaFEV [45]

The answer would be the first person said 6, -26,102

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2 years ago

There are 5 red balls, 4 blue balls, 6 yellow balls and 10 green balls in a box,

lys-0071 [83]

According to given information there are :

5 red balls

4 blue balls

6 yellow balls

10 green balls

<h3>1. what is the probability that the ball chosen is red ?</h3>

$\qquad \sf \dashrightarrow \: p(red) = \dfrac{total \: red \: balls}{total \: balls}$

$\qquad \sf \dashrightarrow \: p(red) = \dfrac{5}{5 + 4 + 6 + 10}$

$\qquad \sf \dashrightarrow \: p(red) = \dfrac{5}{25}$

$\qquad \sf \dashrightarrow \: p(red) = \dfrac{1}{5}$

<h3>2. what is the probability that the ball chosen is blue ?</h3>

$\qquad \sf \dashrightarrow \: p(blue) = \dfrac{total \: blue \: balls}{total \: balls}$

$\qquad \sf \dashrightarrow \: p(blue) = \dfrac{4}{5 + 4 + 6 + 10}$

$\qquad \sf \dashrightarrow \: p(blue) = \dfrac{4}{25}$

<h3>3. what is the probability that the ball chosen is yellow ?</h3>

$\qquad \sf \dashrightarrow \: p(yellow) = \dfrac{total \: yellow\: balls}{total \: balls}$

$\qquad \sf \dashrightarrow \: p(yellow) = \dfrac{6}{5 + 4 + 6 + 10}$

$\qquad \sf \dashrightarrow \: p(yellow) = \dfrac{6}{25}$

<h3>4. what is the probability that the ball chosen is green ?</h3>

$\qquad \sf \dashrightarrow \: p(green) = \dfrac{total \: green\: balls}{total \: balls}$

$\qquad \sf \dashrightarrow \: p(green) = \dfrac{10}{5 + 4 + 6 + 10}$

$\qquad \sf \dashrightarrow \: p(green) = \dfrac{10}{25}$

$\qquad \sf \dashrightarrow \: p(green) = \dfrac{2}{5}$

<h3>5. what is the probability that the ball chosen is not green ?</h3>

$\qquad \sf \dashrightarrow \: p(not \: green) = \dfrac{total \: non \: green\: balls}{total \: balls}$

$\qquad \sf \dashrightarrow \: p(not \: green) = \dfrac{5 + 4 + 6}{5 + 4 + 6 + 10}$

$\qquad \sf \dashrightarrow \: p(not \: green) = \dfrac{15}{25}$

$\qquad \sf \dashrightarrow \: p(not \: green) = \dfrac{3}{5}$

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2 years ago

Find the slope of the line. <br><br> A. 1/3<br> B. - 1/3<br> C. 3<br> D. -3

BARSIC [14]

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

We have the points (0, -2) and (6, 0).

Substitute:

$m=\dfrac{0-(-2)}{6-0}=\dfrac{2}{6}=\dfrac{1}{3}$

<h3>Answer: A. 1/3</h3>

3 0

2 years ago